如何配置aspectj忽略getter和setter

第二个没有编译,因为 within() 需要类型签名,而不是方法签名。你所指的答案完全错了,我不知道为什么会被接受。我刚刚写了 a new one 为了纠正错误信息。

您最后的尝试基本上是正确的,但只会忽略二传手,而不会忽略获得者。尝试以下操作:

驱动程序应用程序:

package de.scrum_master.app;

public class Application {
  private int id;
  private String name;

  public int getId() {
    return id;
  }
  public void setId(int id) {
    this.id = id;
  }
  public String getName() {
    return name;
  }

  public void setName(String name) {
    this.name = name;
  }

  public void doSomething() {
    System.out.println("Doing something");
  }

  public static void main(String[] args) {
    Application application = new Application();
    application.setId(11);
    application.setName("John Doe");
    application.doSomething();
    System.out.println(application.getId() + " - " + application.getName());
  }
}

方面:

package de.scrum_master.aspect;

import org.aspectj.lang.ProceedingJoinPoint;
import org.aspectj.lang.annotation.Around;
import org.aspectj.lang.annotation.Aspect;

@Aspect
public class MyAspect {
  @Around("execution(public * *(..)) && !execution(void set*(*)) && !execution(!void get*())")
  public Object myAdvice(ProceedingJoinPoint thisJoinPoint) throws Throwable {
    System.out.println(thisJoinPoint);
    return thisJoinPoint.proceed();
  }
}

控制台日志:

execution(void de.scrum_master.app.Application.main(String[]))
execution(void de.scrum_master.app.Application.doSomething())
Doing something
11 - John Doe

请注意

• 如果有布尔值的getter,如 isActive() 如果要忽略它们,必须通过以下方式扩展切入点 && !execution(boolean is*()) .
• 那些带有名称模式的切入点总是启发式的,所以要小心方法名称,例如 getaway , settleConflict , isolate . 他们也会被忽视。