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如何使用E4X删除特定类型的所有节点?

e4x actionscript-3 xml

1

1.21 gigawatts · 技术社区 · 9 年前

我有一个XML实例,它有许多节点需要删除。我知道如何获取这些节点的列表,但如何删除它们?之后,我将不得不向XMLList中添加新项。不确定这是否会改变答案。我看到XMLList上有一个replace()方法。

操作脚本:

var xmllist:XMLList = myXML.Hyperlink;

XML格式:

<Document>
    <HyperlinkURLDestination Self="HyperlinkURLDestination/http%3a//test.com#1stMultilineLink/" DestinationUniqueKey="1" Name="http://test.com#1stMultilineLink/" DestinationURL="http://test.com#1stMultilineLink/" Hidden="false"/>
    <HyperlinkURLDestination Self="HyperlinkURLDestination/http%3a//test.com#inlinehyperlink_noshareddestination" DestinationUniqueKey="2" Name="http://test.com#inlinehyperlink_noshareddestination" DestinationURL="http://test.com#inlinehyperlink_noshareddestination" Hidden="true"/>
    <HyperlinkURLDestination Self="HyperlinkURLDestination/http%3a//google.com#multilinehyperlink" DestinationUniqueKey="3" Name="http://google.com#multilinehyperlink" DestinationURL="http://google.com#multilinehyperlink" Hidden="false"/>
    <Hyperlink Self="ufc" Name="is a  multiline hyperlink that terminates here" Source="uf9" Visible="false" Highlight="None" Width="Thin" BorderStyle="Solid" Hidden="false" DestinationUniqueKey="1">
        <Properties>
            <BorderColor type="enumeration">Black</BorderColor>
            <Destination type="object">HyperlinkURLDestination/http%3a//test.com#1stMultilineLink/</Destination>
        </Properties>
    </Hyperlink>
    <Hyperlink Self="u112" Name="hyperlink inline" Source="u111" Visible="false" Highlight="None" Width="Thin" BorderStyle="Solid" Hidden="false" DestinationUniqueKey="2">
        <Properties>
            <BorderColor type="enumeration">Black</BorderColor>
            <Destination type="object">HyperlinkURLDestination/http%3a//test.com#inlinehyperlink_noshareddestination</Destination>
        </Properties>
    </Hyperlink>
    <Hyperlink Self="u137" Name="another multline hyperlink" Source="u136" Visible="false" Highlight="Outline" Width="Thick" BorderStyle="Solid" Hidden="false" DestinationUniqueKey="3">
        <Properties>
            <BorderColor type="enumeration">Purple</BorderColor>
            <Destination type="object">HyperlinkURLDestination/http%3a//google.com#multilinehyperlink</Destination>
        </Properties>
    </Hyperlink>
</Document>

1 回复 | 直到 9 年前

1

1.21 gigawatts 9 年前

好的。我找到了一些方法。

方法1。使用XMLListCollection。这将从原始XML中删除项目:

var hyperlinksList:XMLList = myXML.Hyperlink;
var myXMLListCollection:XMLListCollection = new XMLListCollection(hyperlinksList);
myXMLListCollection.removeAll();

方法2。直接从XML中删除节点:

delete myXML.Hyperlink;

然后,我可以使用XMLListCollection.addItem()再次添加它们:

myXMLListCollection.addItem(<Hyperlink id="mylink"/>);