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如何在键之间均匀分布总值数

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user3742796 · 技术社区 · 7 年前

如何在键之间均匀分布值的总数。

我正在尝试将值均匀分布到关键点。我不希望值vcn[01-05]和vcn[06-10]分别位于vsn01和vsn02键下。相反,我希望vcn[01,03,05,07,09]和vcn[02,04,06,08,10]分别位于vsn01和vsn02键下。

例如

值的数目:-

vcn01
vcn02
vcn03
vcn04
vcn05
vcn06
vcn07
vcn08
vcn09
vcn10

钥匙

vsn01
vsn02

所需输出

vsn01

vcn01
vcn03
vcn05
vcn07
vcn09

vsn02

vcn02
vcn04
vcn06
vcn08
vcn10

注:-

钥匙总数-20,即vsn[01-20]

数值总数-100,即vcn【01-100】

已尝试:-

#! /bin/bash


function create_vsn_vcn_lists ()
{
    pnode_cnt=$1
    vcn_cnt=$2

    declare -a vcn_lists
    for i in `seq $pnode_cnt`; do
        ${vcn_lists[${i}]}=''
    done

    for i in `seq $vcn_cnt`; do
        for j in `seq $pnode_cnt`; do
            ret=`expr ${i} % ${j}`
            if [ $ret -eq 0 ]; then
                ${vcn_lists[${j}]}="${vcn_lists[${j}]} vcn${i}"
            fi
        done
    done

    for i in `seq $pnode_cnt`; do
        echo ${vcn_lists[${j}]}
    done

}

create_vsn_vcn_lists 2 20

3 回复 | 直到 7 年前

Ed Morton 7 年前

看见 https://unix.stackexchange.com/questions/169716/why-is-using-a-shell-loop-to-process-text-considered-bad-practice 对于一些您不应该尝试在shell中像这样操纵文本的原因。编写shell的人也为shell编写了awk来调用来操纵文本,所以就使用它吧。

如果您的输入仅为您发布的脚本中显示的2个数字( create_vsn_vcn_lists ):

$ cat tst.awk
BEGIN {
    for (keyNr=1; keyNr<=numKeys; keyNr++) {
        printf "vsn%02d\n\n", keyNr
        for (valNr=keyNr; valNr<=numVals; valNr+=numKeys) {
            printf "vcn%02d\n", valNr
        }
        print ""
    }
}

。

$ awk -v numKeys=2 -v numVals=10 -f tst.awk
vsn01

vcn01
vcn03
vcn05
vcn07
vcn09

vsn02

vcn02
vcn04
vcn06
vcn08
vcn10

或者如果您的输入是两个独立的文件,就像您发布的示例输入中显示的那样( number of values 和 keys ):

$ cat tst.awk
NR==FNR {
    keys[++numKeys] = $0
    next
}
{
    keyNr = ((FNR-1) % numKeys) + 1
    vals[keyNr] = (keyNr in vals ? vals[keyNr] ORS : "") $0
}
END {
    for (keyNr=1; keyNr<=numKeys; keyNr++) {
        print keys[keyNr] ORS ORS vals[keyNr] ORS
    }
}

。

$ awk -f tst.awk keys values
vsn01

vcn01
vcn03
vcn05
vcn07
vcn09

vsn02

vcn02
vcn04
vcn06
vcn08
vcn10

RavinderSingh13 Nikita Bakshi 7 年前

你能试试下面的吗 awk 如果这对你有帮助,请告诉我。

awk -v count=$(wc -l < keys) 'FNR==NR{a[++i]=$0;next} {b[FNR]=$0} END{for(k=1;k<=count;k++){print b[k] ORS;for(j=k;j<=i;j+=count){print a[j]};print "********"}}' number_of_values keys

在这里也添加了一个非线性形式的解决方案。

awk -v count=$(wc -l < keys) '
FNR==NR{
  a[++i]=$0;
  next}
{
  b[FNR]=$0
}
END{
  for(k=1;k<=count;k++){
     print b[k] ORS;
  for(j=k;j<=i;j+=count){
     print a[j]};
     print "********"}
}
' number_of_values keys

说明: 在此处也添加代码解释。

awk -v count=$(wc -l < keys) '  ##Creating a variable named count whose value is the number of lines in Input_file named keys.
FNR==NR{                        ##Checking condition here if FNR==NR which will be TRUE when first Input_file is being read.
  a[++i]=$0;                    ##Creating an array named a whose index is variable i whose value is getting incremented each time with 1 and value is current line.
  next}                         ##next keyword will skip all further statements from here on wards, since we do not want to execute them now.
{
  b[FNR]=$0                     ##This statement will be executed when 2nd Input_file named keys is being read. Creating array named b whose value is $0 with index FNR.
}
END{                            ##Starting END section of awk here now.
  for(k=1;k<=count;k++){        ##Starting a for loop whose value starts from k=1 to till value of variable count.
     print b[k] ORS;            ##Printing the value of array b whose index is k and ORS whose default value is new line.
  for(j=k;j<=i;j+=count){       ##Starting a for loop here which starts from j=k to till value of variable i and increment happens with count variable increment.
     print a[j]};               ##Printing value of array a whose index is variable j.
     print "********"}          ##Printing ******** here to segregate between different output sets.
}
' number_of_values keys         ##Mentioning the Input_file names here.

CrazyApe84 7 年前

这个怎么样?

#!/bin/bash

function create_vsn_vcn_lists {
    local vsn_cnt=$1 vcn_cnt=$2 start=1 i j
    for ((i=1; i<=vsn_cnt; ++i, ++start)); do
        printf "vsn%02d\n\n" $i
        for ((j=start; j<=vcn_cnt; j+=vsn_cnt)); do
            printf "vcn%02d\n" $j
        done
        echo
    done
}

create_vsn_vcn_lists 3 10

输出:

vsn01

vcn01
vcn04
vcn07
vcn10

vsn02

vcn02
vcn05
vcn08

vsn03

vcn03
vcn06
vcn09