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如何将属性值存储到表单中的输入

  •  0
  • user8579791  · 技术社区  · 7 年前

    Jquery代码

      //active image setting
        $('#allimg li:first').addClass('activeimg');
      //code for like and next image  
       $('.clickme').on('click', function() {
           var tagname = $('.activeimg img').attr('name');
         $('.activeimg').removeClass('activeimg').next('#allimg li').addClass('activeimg');
    
       if (tagname) {
        var result = $('#resultdiv');
        var text = result.text().trim();
        if (text) {
            text += ',';
        }
        result.text(text + tagname);
       } 
      });
    
        //code for next image only
    
        $('.nextme').on('click', function() {
            $('.activeimg').removeClass('activeimg').next('#allimg li').addClass('activeimg');
        });
    

    货物堆装与系固安全操作规则

    .menu_card ul {
        list-style-type: none;
    }
    .menu_card ul li img{
        width: 200px;
        height: 300px;
    }
    .menu_card ul li{
        list-style-type: none;
        position: absolute;
        display: none;
    }
    .menu_card ul li.activeimg{
        list-style-type: none;
        position: absolute;
        display: block;
    }
    

    html代码

      <form method="post" action="">
           <div class="row">
            <div class="col-12">
               <div class="menu_card">
                 <ul id="allimg">
                   <li><img name="one" src="imges/img1.jpg"></li>
                    <li><img name="two" src="imges/img2.jpg"></li>
                      <li><img name="three" src="imges/img3.jpg"></li>
                    <li><img name="four" src="imges/img4.jpg"></li>
                   <li><img name="five" src="imges/img5.jpg"></li>
                 </ul> 
               </div>  
            </div>  
          </div>
           <div class="row">
               <!--- button / next button-->
                <div class="col-1" style="margin-top: 350px;color:red">
                   <div class="pull-right nextme">
                       <i class="fa fa-thumbs-o-down fa-3x"></i> <br/>
                        Unike
                   </div>
                </div>
                <!---Like button / next button (one button for all image)-->
                <div class="col-2" style="margin-top:350px;color:green">
                   <div class="pull-right clickme">
                       <i class="fa fa-thumbs-o-up fa-3x"></i> <br/>
                        Like
                   </div>
                </div>
             </div>
            <div class="row">
             <div class="col-12 text-center" id="resultdiv">
                 <input type="hidden" value="">
             </div> 
            </div>
    
            <br/>
            <input type="submit" class="btn btn-success">
          </form>
    

    请帮帮我。

    2 回复  |  直到 7 年前
        1
  •  0
  •   Klaus Mikaelson    7 年前

    我对你的代码做了一些更改。如果你想要这个。

    //active image setting
    var vals = '';
        $('#allimg li:first').addClass('activeimg');
      //code for like and next image  
       $('.clickme').on('click', function() {
           var tagname = $('.activeimg img').attr('name');
         $('.activeimg').removeClass('activeimg').next('#allimg li').addClass('activeimg');
    
       if (tagname) {
       vals += tagname+',';
       $('.vals').val(vals);
       
       // var result = $('#resultdiv');
       // var text = result.text().trim();
        //if (text) {
         //   text += ',';
        //}
       // result.text(text + tagname);
       } 
      });
    
        //code for next image only
    
        $('.nextme').on('click', function() {
            $('.activeimg').removeClass('activeimg').next('#allimg li').addClass('activeimg');
        });
        $('.submitBTN').on('click', function() {
            
            alert(vals);
        });
    .menu_card ul {
        list-style-type: none;
    }
    .menu_card ul li img{
        width: 200px;
        height: 300px;
    }
    .menu_card ul li{
        list-style-type: none;
        position: absolute;
        display: none;
    }
    .menu_card ul li.activeimg{
        list-style-type: none;
        position: absolute;
        display: block;
    }
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
    <form method="post" action="">
           <div class="row">
            <div class="col-12">
               <div class="menu_card">
                 <ul id="allimg">
                   <li><img name="one" src="https://dummyimage.com/600x400/555/fff"></li>
                    <li><img name="two" src="https://dummyimage.com/600x400/000/fff"></li>
                      <li><img name="three" src="https://dummyimage.com/600x400/536/fff"></li>
                    <li><img name="four" src="https://dummyimage.com/600x400/698/fff"></li>
                   <li><img name="five" src="https://dummyimage.com/600x400/742/fff"></li>
                 </ul> 
               </div>  
            </div>  
          </div>
           <div class="row">
               <!--- button / next button-->
                <div class="col-1" style="margin-top: 350px;color:red">
                   <div class="pull-right nextme">
                       <i class="fa fa-thumbs-o-down fa-3x"></i> <br/>
                        Unike
                   </div>
                </div>
                <!---Like button / next button (one button for all image)-->
                <div class="col-2" style="margin-top:350px;color:green">
                   <div class="pull-right clickme">
                       <i class="fa fa-thumbs-o-up fa-3x"></i> <br/>
                        Like
                   </div>
                </div>
             </div>
            <div class="row">
             <div class="col-12 text-center" id="resultdiv">
                 
             </div> 
             <input type="hidden" class="vals" value=''>
            </div>
    
            <br/>
            <input type="submit" class="btn btn-success submitBTN">
          </form>
        2
  •  0
  •   Rakesh Raj    7 年前

    添加 Id 到隐藏输入 <input id="data" type="hidden" value="">

    <script>
    if (tagname) {
                    var result = $('#data');
                   var text = result.val(); 
                   if (text) {
                            text += ',';
                        }   
                   result.attr('value',text + tagname);
    </script>