具有上限的int列表的再分配

您可以编写一个自定义函数来实现这一点——不需要大量依赖项。请注意,这将返回一个 新 列表可以通过创建一个类来进一步改进这一点:

def generate_list_with_normalization(input_list, element_to_add, cap=100):
    total = sum(input_list) + element_to_add
    
    if total <= cap:
        return input_list + [element_to_add]
    return [elem * cap / total for elem in input_list + [element_to_add]]

my_list = [10, 5, 20, 30, 25, 10]
result = generate_list_with_normalization(my_list, 10, 100)
print(result)
print(sum(result))

这将产生:

[9.090909090909092, 4.545454545454546, 18.181818181818183,
27.272727272727273, 22.727272727272727, 9.090909090909092, 9.090909090909092]
100.0

你可以使用:

my_list = [10, 5, 20, 30, 25, 10]
add = 10

sub = (100-sum(my_list)-add)/len(my_list)

new_list = [x+sub for x in my_list]+[add]
# [8.33, 3.33, 18.33, 28.33, 23.33, 8.33, 10]

sum(new_list)
# 100