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TypeError:无法在字符串上创建属性“\u id”…即使使用JSON.Parse(MongoDB/Node.js/Twitter API)

twitter mongodb node.js

E Alexis MT · 技术社区 · 6 年前

我正在尝试将Tweets的文本(使用twitterapi)插入MongoDB数据库,我得到了 TypeError: Cannot create property _id on string

var Twitter = require('twitter');
var fs = require("fs");
var request = require("request");

var client = new Twitter({
  consumer_key: ' ',
  consumer_secret: ' ',
  access_token_key: ' ',
  access_token_secret: ' '});

var MongoClient = require('mongodb').MongoClient;
var url = "mongodb://localhost:27017/mydb";
var parser = { useNewUrlParser: true };

    MongoClient.connect(url, parser, function(err, db) {
      if (err) throw err;
      console.log("Database created!");
      var dbo = db.db("mydb");
      dbo.createCollection("datos_sentimiento", function(err, res) {
        if (err) throw err;
        console.log("Collection created!");
        db.close();
      });
    });

MongoClient.connect(url, parser, function(err, db) {
  if (err) throw err;
  var dbo = db.db("mydb");
  var cont = 0;

  var params = {q: '@Avengers', count: 100, include_rts: 0, tweet_mode: 'extended', retweeted_status: 'extended'};
  client.get('search/tweets', params, function(error, tweets, response) {
  if (!error) {
      //console.log(tweets);
      for(var i=0; i < params.count; i++){

        if(tweets.retweeted_status){
          tweets = tweets.retweeted_status;
          var tweet = (JSON.stringify(tweets.statuses[i])+"\n");
          var string = tweet.replace(/[&\/\\#,+()$~%.'":*?<>{}]/g, '');
          console.log('hi');
        }
        else{

          //console.log('hi2');
        }

        var tweet = (JSON.stringify(tweets.statuses[i].full_text));
        var string = tweet.replace(/[&\/\\#,+()$~%.'":*?<>{}]/g, '');
        var string2 = (JSON.stringify(string)+"\n");

        fs.appendFile("tweet.txt", string2, function (err) {
          if (err) throw err;
            //console.log('Saved!');
        }); 

        /*console.log(cont);
        cont++;*/

        var myobj = JSON.parse(string2);

        console.log("hi "+myobj);
        dbo.collection("datos_sentimiento").insertOne(myobj, function(err, res) {
          if (err) throw err;
          console.log("1 document inserted");
          db.close();
        });
        //console.log(i+'fdfdfdfdf');

        }
      }
  });
});

错误显示以下消息:

TypeError: Cannot create property '_id' on string 'RT @RobertDowneyJr Brace yourselves @Avengers InfinityWar hits the interwebs today httpstcoqvBQ3W8jvc'

2 回复 | 直到 6 年前

E Alexis MT 6 年前

我找到了解决办法。MongoDB需要(必须有!)有一个文档(例如text={screen\u name:name,text:text})。我的更正如下:

var text = JSON.parse(string2);
var myobj = {texto: text};

console.log("hi "+text);
dbo.collection("datos_sentimiento").insertOne(myobj, function(err, res) {
    if (err) throw err;
        console.log("1 document inserted");
    db.close();
});

Vikash_Singh 5 年前

变量 myobj {myobj} :

dbo.collection("datos_sentimiento").insertOne(myobj, function(err, res) {

修改为: dbo.collection("datos_sentimiento").insertOne({myobj}, function(err, res) {