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如何动态更新数据表中的单元格?

  •  3
  • abu abu  · 技术社区  · 6 年前

    我正在使用 this 数据项。

    我的代码如下

    table = $('#invoices-table').DataTable({ ordering: false });
    var currentPage = table.page();
    
    rowNode = table.row.add([
        table_sr_no,
        '<a href="/view_debit_notes/' + data.id + '" class="view_debit_notes">' + data.debitnote_no + '</a>',
        '<td class="text-right">' + data.total + '</td>',
        'Serial No',
        '',
        '<a href="/seller/number">Active</a>',
        ''
    ]).draw();
    
    var index = 0,
    rowCount = table.data().length - 1,
    insertedRow = table.row(rowCount).data(),
    tempRow;
    
    for (var i = rowCount; i > index; i--) {
        tempRow = table.row(i - 1).data();
        table.row(i).data(tempRow);
        table.row(i - 1).data(insertedRow);
    }
    
    table.page(currentPage).draw(false);
    

    我将在第一个位置插入一行,在之前生成的表中使用下面的代码。

    rowNode = table.row.add([
            table_sr_no,
            '<a href="/view_debit_notes/' + data.id + '" class="view_debit_notes">' + data.debitnote_no + '</a>',
            '<td class="text-right">' + data.total + '</td>',
            'Serial No',
            '',
            '<a href="/seller/number">Active</a>',
            ''
        ]).draw();
    

    我想我必须在下面的代码中做一些事情来重新生成 新序列号

    for (var i = rowCount; i > index; i--) {
        tempRow = table.row(i - 1).data();
        table.row(i).data(tempRow);
        table.row(i - 1).data(insertedRow);
    }
    

    如何动态生成序列号( 表1 )多少?

    我需要 序列号 像下面

    enter image description here

    1 回复  |  直到 6 年前
        1
  •  1
  •   Eaten by a Grue kackleyjm    6 年前

    根据您的意见,我的理解是您希望第一列或多或少像自动增量一样工作,其中每个单元格都包含一个引用其在表中位置的数字。可以将每行中的第一个单元格设置为父行的索引,如下所示:

    // select first cell in every row and iterate over them
    $('#invoices-table tr td:first-child').each( function() {
        // get a reference to the datatable's cell and assign
        // the parent row's index as content
        table.cell(this).data($(this).parent().index()+1);
    });
    // redraw the table so new cell data will work with sorting and filtering
    table.draw();
    

    更新:

    我将在这里提供另一个解决方案,因为我意识到上面的内容将在分页/行当前不可见的表上失败。数据表提供了它自己的 each() 可以在集合中的节点上调用的方法。要使用它,您可以这样做:

    table.cells(':first-child').nodes().each(function(node, index) {
        table.cell(node).data(index + 1);
    });
    

    你会注意到这是 非常相似 按照我最初的建议,但是它还有一个额外的好处 全部的 行而不仅仅是可见行。

    下面是一段演示:

    var dataSet = [
      ["", "Tiger Nixon", "System Architect", "Edinburgh", "5421", "2011/04/25", "$320,800"],
      ["", "Garrett Winters", "Accountant", "Tokyo", "8422", "2011/07/25", "$170,750"],
      ["", "Ashton Cox", "Junior Technical Author", "San Francisco", "1562", "2009/01/12", "$86,000"],
      ["", "Cedric Kelly", "Senior Javascript Developer", "Edinburgh", "6224", "2012/03/29", "$433,060"],
      ["", "Airi Satou", "Accountant", "Tokyo", "5407", "2008/11/28", "$162,700"],
      ["", "Brielle Williamson", "Integration Specialist", "New York", "4804", "2012/12/02", "$372,000"],
      ["", "Herrod Chandler", "Sales Assistant", "San Francisco", "9608", "2012/08/06", "$137,500"],
      ["", "Rhona Davidson", "Integration Specialist", "Tokyo", "6200", "2010/10/14", "$327,900"],
      ["", "Colleen Hurst", "Javascript Developer", "San Francisco", "2360", "2009/09/15", "$205,500"],
      ["", "Sonya Frost", "Software Engineer", "Edinburgh", "1667", "2008/12/13", "$103,600"],
      ["", "Jena Gaines", "Office Manager", "London", "3814", "2008/12/19", "$90,560"],
      ["", "Quinn Flynn", "Support Lead", "Edinburgh", "9497", "2013/03/03", "$342,000"],
      ["", "Charde Marshall", "Regional Director", "San Francisco", "6741", "2008/10/16", "$470,600"],
      ["", "Haley Kennedy", "Senior Marketing Designer", "London", "3597", "2012/12/18", "$313,500"],
      ["", "Tatyana Fitzpatrick", "Regional Director", "London", "1965", "2010/03/17", "$385,750"],
      ["", "Michael Silva", "Marketing Designer", "London", "1581", "2012/11/27", "$198,500"],
      ["", "Paul Byrd", "Chief Financial Officer (CFO)", "New York", "3059", "2010/06/09", "$725,000"],
      ["", "Gloria Little", "Systems Administrator", "New York", "1721", "2009/04/10", "$237,500"],
      ["", "Bradley Greer", "Software Engineer", "London", "2558", "2012/10/13", "$132,000"],
      ["", "Dai Rios", "Personnel Lead", "Edinburgh", "2290", "2012/09/26", "$217,500"],
      ["", "Jenette Caldwell", "Development Lead", "New York", "1937", "2011/09/03", "$345,000"],
      ["", "Yuri Berry", "Chief Marketing Officer (CMO)", "New York", "6154", "2009/06/25", "$675,000"],
      ["", "Caesar Vance", "Pre-Sales Support", "New York", "8330", "2011/12/12", "$106,450"],
      ["", "Doris Wilder", "Sales Assistant", "Sidney", "3023", "2010/09/20", "$85,600"],
      ["", "Angelica Ramos", "Chief Executive Officer (CEO)", "London", "5797", "2009/10/09", "$1,200,000"],
      ["", "Gavin Joyce", "Developer", "Edinburgh", "8822", "2010/12/22", "$92,575"],
      ["", "Jennifer Chang", "Regional Director", "Singapore", "9239", "2010/11/14", "$357,650"],
      ["", "Brenden Wagner", "Software Engineer", "San Francisco", "1314", "2011/06/07", "$206,850"],
      ["", "Fiona Green", "Chief Operating Officer (COO)", "San Francisco", "2947", "2010/03/11", "$850,000"],
      ["", "Shou Itou", "Regional Marketing", "Tokyo", "8899", "2011/08/14", "$163,000"],
      ["", "Michelle House", "Integration Specialist", "Sidney", "2769", "2011/06/02", "$95,400"],
      ["", "Suki Burks", "Developer", "London", "6832", "2009/10/22", "$114,500"],
      ["", "Prescott Bartlett", "Technical Author", "London", "3606", "2011/05/07", "$145,000"],
      ["", "Gavin Cortez", "Team Leader", "San Francisco", "2860", "2008/10/26", "$235,500"],
      ["", "Martena Mccray", "Post-Sales support", "Edinburgh", "8240", "2011/03/09", "$324,050"],
      ["", "Unity Butler", "Marketing Designer", "San Francisco", "5384", "2009/12/09", "$85,675"]
    ];
    
    $(document).ready(function() {
      var table = $('#example').DataTable({
        data: dataSet,
        columns: [
          {title: "Row ID"},
          {title: "Name"},
          {title: "Position"},
          {title: "Office"},
          {title: "Extn."},
          {title: "Start date"},
          {title: "Salary"}
        ]
      });
      $('button').on('click', function() {
        table.cells(':first-child').nodes().each(function(node, index) {
          table.cell(node).data(index + 1);
        });
        // redraw table and keep current pagination
        table.draw(false);
      });
    });
    <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
    <script src="https://cdn.datatables.net/1.10.19/js/jquery.dataTables.min.js"></script>
    <link href="https://cdn.datatables.net/1.10.19/css/jquery.dataTables.min.css" rel="stylesheet" />
    
    <button>Click to reindex table</button><br><br>
    <table id="example" class="display" width="100%"></table>