使用system.diagnostics.process将y输入到标准输入上的plink?

我如何通过 Y 进入由 System.Diagnostic.Process 在动力壳牌?

function Start-NewPlinkProcess(
        [string]$pfile = 'plink.exe',
        [string]$arguments = 'somehost -l somelogin -pw somepasswd ping -c 12 someOtherHost > /home/homeie/mePingTestResults.txt'
    ){
    $p = New-Object System.Diagnostics.Process;
    $p.StartInfo.UseShellExecute = $false;
    $p.StartInfo.RedirectStandardOutput = $true;
    $p.StartInfo.RedirectStandardInput = $true;
    $p.StartInfo.FileName = $pfile;
    $p.StartInfo.Arguments = $arguments
    $p.StandardInput.WriteLine("Y") # Pass a Y to stdin ignore that...
    $pident = ($p.Start()).Id
    Write-Host("pid: $($pident)");
    #$p.WaitForExit();
    #$p.StandardOutput.ReadToEnd();
    return $p
}

当我叫它的时候,我仍然得到:

If you trust this host, enter "y" to add the key to
PuTTY's cache and carry on connecting.
If you want to carry on connecting just once, without
adding the key to the cache, enter "n".
If you do not trust this host, press Return to abandon the
connection.
Store key in cache? (y/n)

我在别处读到过,有可能尝试 echo y | plink ... 让它从标准输入端以管道的形式读取它,但我希望对它有更多的控制,然后就这样。