在两个列表中查找公共元素

这相当于使用列表理解的循环:

[print e for e in list_1 for k in list_2 if k in e]

首先我会调查 itertools.product() 然后我就不会用列表来理解副作用,例如:

import itertools as it

print '\n'.join(e for e, k in it.product(list_1, list_2) if k in e)

我也会考虑 __future__ 使用 print_function 例如:

from __future__ import print_function
import itertools as it

print('\n'.join(e for e, k in it.product(list_1, list_2) if k in e))

@ Petpan ,你可以使用 list comprehension 满足你的需要。

你不应该用列表理解的方法。

在线试用 http://rextester.com/QBQDO38144 .

list_1 = ['rwww corp\pan 2323 2018-23-23 0% c:\program files\pa.txt', 
          'rwww corp\pand 2323 2018-23-23 0% c:\program files\monkey.txt', 
          'c:\program files\pa.txt',
          'c:\program files\pex2.txt',
          'c:\program files\pex5.txt',
          'c:\program files\pex4.txt',
          ]

list_2 = ['c:\program files\pa.txt', 'c:\program files\pex2.txt', 'c:\program files\pex3.txt',]

# You should not use list comprehension for this purpose
# It will print items in list_1 if it also exists in list_2
[print(e, 'exists in list_1') for e in list_2 if e in list_1]

产量

c:\program files\pa.txt exists in list_1
c:\program files\pex2.txt exists in list_1