非聚合根是否可以保存另一个非聚合根的引用?

如果我有 two aggregates

第一次聚合:

• 工作时间
• 调节作用

数据澄清:

工作时间规定:

 public class WorkTimeRegulation : Entity<Guid>, IAggregateRoot
    {
        private WorkTimeRegulation()//COMB
       : base(Provider.Sql.Create()) // required for EF
        {
        }
        private WorkTimeRegulation(Guid id) : base(id)
        {
            _assignedWorkingTimes = new List<WorkingTime>();
            _enrolledParties = new List<RegulationEnrolment>();
        }
        private readonly List<WorkingTime> _assignedWorkingTimes;
        private readonly List<RegulationEnrolment> _enrolledParties;
        public string Name { get; private set; }
        public byte NumberOfAvailableRotations { get; private set; }
        public bool IsActive { get; private set; }
        public virtual IEnumerable<WorkingTime> AssignedWorkingTimes { get => _assignedWorkingTimes; }
       public virtual IEnumerable<RegulationEnrolment> EnrolledParties { get => _enrolledParties; }
        //...
    }

Id|    Name            |   NumberOfAvailableRotations|  IsActive 

 1|    General Rule    |          2                  |    true   

工作时间:

public class WorkTime : Entity<Guid>
    {
        private WorkTime()
      : base(Provider.Sql.Create()) // required for EF
        {
        }
        private WorkTime(Guid id) : base(id)
        {
            ActivatedWorkingTimes = new List<WorkingTimeActivation>();
        }
        private ICollection<WorkingTimeActivation> _activatedWorkingTimes;

        public string Name { get; set; }
        public byte NumberOfHours { get; set; }
        public byte NumberOfShortDays { get; set; }
        public Guid WorkTimeRegulationId { get; private set; }
        public virtual ICollection<WorkingTimeActivation> ActivatedWorkingTimes { get => _activatedWorkingTimes; private set => _activatedWorkingTimes = value; }
        //....
   }

Id|  Name   |   NumberOfHours| NumberOfShortDays |WorkTimeRegulationId 

1 | Winter  |     8          |    1              |    1
2 | Summer  |     6          |    0              |    1

第二个聚合:

• 移位(根)
• 移位细节
• 移位控制

数据澄清:

  public class Shift : Entity<Guid>, IAggregateRoot
    {
        private readonly List<ShiftDetail> _assignedShiftDetails;
        private readonly List<ShiftEnrolment> _enrolledParties;


        public string Name { get; set; }
        public ShiftType ShiftType { get; set; }
        public int WorkTimeRegulationId { get; set; }
        public bool IsDefault { get; set; }
        public virtual WorkingTimeRegulation WorkTimeRegulation { get; set; }
        public virtual IEnumerable<ShiftDetail> AssignedShiftDetails { get => _assignedShiftDetails; }
        public virtual IEnumerable<ShiftEnrolment> EnrolledParties { get => _enrolledParties; }
        //...........
   }

Id|  Name      |  ShiftType  |  WorkTimeRegulationId  | IsDefault 
1 | IT shift   |  Morning    |    1                   |  1 

移位详细信息:

  public class ShiftDetail : Entity<Guid>
    {
        public Guid ShiftId { get; private set; }
        public Guid WorkTimeId { get; private set; }
        public DateTimeRange ShiftTimeRange { get; private set; }
        public TimeSpan GracePeriodStart { get; private set; }
        public TimeSpan GracePeriodEnd { get; private set; }
        public virtual WorkTime WorkTime { get; private set; }

        private ShiftDetail()
        : base(Provider.Sql.Create()) // required for EF
        {
        }
        //..........
   }

ShiftId  WorkTimeId shift-start  shift-end   
  1          1        08:00        16:00
  1          2        08:00        14:00

我的问题是:

• ShiftDetail )保存参考文献 对于另一个非聚合根( WorkTime

• 领域专家澄清:要创建一个有效的移位,那么我们 应该有一个 shift detail 为每一个 worktime 与 worktimeRegulation . 无法更新中的工作小时数 工作时间 shiftDetails . 前面的例子表明 有 two worktimes(winter,summer) ,所以我们有一个 shiftdetai l代表 winter 坚持 8 shiftdetail 对于 summer 坚持 6 工作时间 )如何强制这个不变量?

• 根据前面的信息,我是否犯了与骨料规格相关的错误?