C宏-如何将宏名设置为另一个宏的输出

#define  JOIN(a,b)       a ## b

#define  FOO(suffix)     JOIN(FOO_, suffix)
#define  FOOBAZ          JOIN(FOO_, BAZ)
#define  FOOBAAZ         JOIN(foo_, baaz)

#define  FOO_BAR         first
#define  FOO_BAZ         second

int FOO(BAR) = 1;
int FOOBAZ = 2;
int FOOBAAZ = 3;

int first = 1;
int second = 2;
int foo_baaz = 3;

#if defined(TYPE) && defined(PREFIX)
#undef   JOIN2
#define  JOIN2_(a,b)  a ## b
#define  JOIN2(a,b)   JOIN2_(a, b)
#define  NAME(end)    JOIN2(PREFIX, end)

static inline TYPE NAME(_add)(const TYPE val1, const TYPE val2)
{
    return val1 + val2;
}

static inline TYPE NAME(_sub)(const TYPE val1, const TYPE val2)
{
    return val1 - val2;
}

static inline TYPE NAME(_neg)(const TYPE val)
{
    return -val;
}

static inline TYPE NAME(_mul)(const TYPE val1, const TYPE val2)
{
    return val1 * val2;
}

static inline TYPE NAME(_div)(const TYPE val1, const TYPE val2)
{
    return val1 / val2;
}

#endif

#undef   NAME
#undef   JOIN2
#undef   PREFIX
#undef   TYPE

NAME(suffix) PREFIX suffix

NAME(_add) (const TYPE val1, const TYPE val2)

#include <stdlib.h>
#include <inttypes.h>
#include <stdio.h>

#define  TYPE    uint32_t
#define  PREFIX  u32
#include "ops.h"

#define  TYPE    float
#define  PREFIX  float
#include "ops.h"

#define  TYPE    double
#define  PREFIX  dbl
#include "ops.h"

int main(void)
{
    printf("dbl_div(217.0, 31.0) = %.1f\n", dbl_div(217.0, 31.0));
    printf("u32_sub(4, 2) = %" PRIu32 "\n", u32_sub(4, 2));
    printf("float_mul(1.25f, 72.00f) = %.2ff\n", float_mul(1.25f, 72.00f));
    return EXIT_SUCCESS;
}

#include "ops.h" u32_add() u32_sub() u32_neg() u32_mul() u32_div() float_add() dbl_add()

dbl_div(217.0, 31.0) = 7.0
u32_sub(4, 2) = 2
float_mul(1.25f, 72.00f) = 90.00f

_Generic