C Getopts:管理所有接收的选项和可选操作目标

char flag = 0; // to mark which options were set
int aopt = INT_MAX; // default to INT_MAX if no args delivered
char bemerkung[100];
memset(bemerkung, '\0', 100); // string to receive via '-b'

char option;

while((option = getopt (argc, argv, "m:a:b:")) != EOF){
    switch( option ){
        case 'm': {
            flag = flag | 1;
            break;
        } 
        case 'a': {
            flag = flag | 2;
            char * arg = optarg;
            aopt = atoi(arg);
            if(aopt == 0 && strcmp("0", arg) != 0) // if no valid optarg was entered
                aopt = INT_MAX; // get back the default value
            break;
        }
        case 'b': {
            flag = flag | 4;
            strcpy(bemerkung, optarg);
            break;
        }
        default: {
            fprintf(stderr, "Unknown option entered.\n");
            return -1;
        }
    }
}

// some code here, not touching `flag`

if(flag == 1){
    // deal with `-m`, no optargs
}
if(flag == 2){
    // `-a aopt` called
}
if(flag == 3){
    // `-m -a aopt` called
}

flag -m 需要参数(对于 -米 ./main -m -a 0 结果进入 flag = 1 而不是 flag = 3 .

我该如何为你辩护 -米 OR 正确处理 ?