代码之家 › 专栏 › 技术社区 › Azhar

希望在Xaml中将Cs文件中的列表绑定到网格,而不需要在代码后面添加任何代码

datagrid data-binding wpf .net c#

Azhar · 技术社区 · 14 年前

我想将Xaml文件中的DataGrid与不在代码后面但在cs文件中的collection绑定

我尝试了不同的方法但没有成功,实际上我不想在代码隐藏文件中编写任何代码。

类别代码

public class Employee : INotifyPropertyChanged
{            
    private int _Id;
    private string _FirstName;
    private string _LastName;
    private double _Salary;
    public event PropertyChangedEventHandler PropertyChanged;

    public Employee()
    {
    }
    public Employee(int pId, string pFirstName, string pLastName, double pSalary)
    {
        Id = pId;
        FirstName = pFirstName;
        LastName = pLastName;
        Salary = pSalary;
    }

    public int Id
    {
        set 
        { 
            _Id = value;
            NotifyPropertyChanged("Id");
        }
        get { return _Id; }
    }
    public string FirstName
    {
        set 
        { 
            _FirstName = value;
            NotifyPropertyChanged("FirstName");
        }
        get { return _FirstName; }
    }
    public string LastName
    {
        set 
        { 
            _LastName = value;
            NotifyPropertyChanged("LastName");
        }
        get { return _LastName; }
    }
    public double Salary
    {
        set 
        {             
            _Salary = value;
            NotifyPropertyChanged("Salary");
        }
        get { return _Salary; }
    }
    private void NotifyPropertyChanged(string pProperty)
    {
        if (PropertyChanged != null)
            PropertyChanged(this, new PropertyChangedEventArgs(pProperty)); 
    }
}


public class EmployeeCollection
{
     ObservableCollection<Employee> lstEmp = new ObservableCollection<Employee>();
     public ObservableCollection<Employee> GetEmployees()
     {
          lstEmp.Add(new Employee(1,"Firstname 1", "Lastname 1", 1.1 ));
          lstEmp.Add(new Employee(2, "Firstname 2", "Lastname 2", 2.2));
          lstEmp.Add(new Employee(3, "Firstname 3", "Lastname 3", 3.3));
          lstEmp.Add(new Employee(4, "Firstname 4", "Lastname 4", 4.4));
          lstEmp.Add(new Employee(5, "Firstname 5", "Lastname 5", 5.5));
          lstEmp.Add(new Employee(6, "Firstname 6", "Lastname 6", 6.6));

          return lstEmp;
     }
}

它的Xaml代码

<my:DataGrid  AutoGenerateColumns="true" Margin="20,0,68,10" Name="dataGrid2" Height="135" VerticalAlignment="Bottom" />

2 回复 | 直到 14 年前

svick Raja Nadar 14 年前

如果我能以对我有意义的方式修改类,我会改变 GetEmployees() 到静态属性。你可以直接写( local 是命名空间的命名空间前缀,其中包含 Employee ):

<DataGrid ItemsSource="{x:Static local:Employee.Employees}" />

如果要保持类的原样,请首先声明 ObjectDataProvider 作为一种资源(例如 <Window.Resources> ):

<ObjectDataProvider ObjectType="local:Employee" MethodName="GetEmployees"
    x:Key="employees" />

然后使用它:

<DataGrid ItemsSource="{Binding Source={StaticResource employees}}" />

peterthegreat 14 年前

您要做的是将codebhind文件中的DataContext设置为数据源,然后告诉DataGrid绑定到它。是这样做的:

C#:

public MainWindow()
        {
            InitializeComponent();

            Employee emp = new Employee();
            DataContext = emp.GetEmployees();

        }

XAML:

<DataGrid  AutoGenerateColumns="true" Margin="20,0,68,10" Name="dataGrid2" Height="135" VerticalAlignment="Bottom" ItemsSource="{Binding}" />