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如何通过xpath在网站上单击每个名称?

webdriver xpath selenium-webdriver selenium python

Nathan123 · 技术社区 · 6 年前

我想用 driver.find_element_by_xpath page

我有下面一段代码,作为一个例子,只需点击一个人的名字

python_button=driver.find_element_by_xpath("""//*[@id="search_results_people_search_832248975"]/div[3]/div[1]/div[1]/div[2]/a/h3""")
python_button.click()

raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.WebDriverException: Message: unknown error: Element <h3 data-bind="text: personDispNm">...</h3> is not clickable at point (387, 558). Other element would receive the click: <div>...</div>

我该如何解决这个问题

3 回复 | 直到 6 年前

undetected Selenium 6 年前

通过网站上的xpath单击每个名称 https://www.dechert.com/content/dechert/en/people.html#firstName=&lastInitial=&lastName=&office=Philadelphia&page=1&q=&school=Villanova+University 你需要等待姓名然后收集 href公司 顺序遍历的属性如下:

代码块:

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

hrefs= []
base_url = "https://www.dechert.com/content/dechert/en/people.html#firstName=&lastInitial=&lastName=&office=Philadelphia&page=1&q=&school=Villanova+University" 
options = webdriver.ChromeOptions() 
options.add_argument("start-maximized")
options.add_argument('disable-infobars')
driver=webdriver.Chrome(chrome_options=options, executable_path=r'C:\Utility\BrowserDrivers\chromedriver.exe')
driver.get(base_url)
persons = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//div[@class='name']//a[contains(@href,'/people/')]")))
for person in persons:
    hrefs.append(person.get_attribute("href"))
for href in hrefs:
    driver.get(href)
    print(driver.current_url)
    driver.get(base_url)

https://www.dechert.com/people/b/april-banko.html
https://www.dechert.com/people/c/nicholas-carroll.html
https://www.dechert.com/people/e/william-elder.html
https://www.dechert.com/people/g/joe-gribbin.html
https://www.dechert.com/people/t/joseph-tate.html
https://www.dechert.com/people/t/marissa-tribuiani.html

或许您也可以使用@Andersson的解决方案,该解决方案经过如下修改后近乎完美:

links = [link.get_attribute('href') for link in WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//div[@class='name']//a[contains(@href,'/people/')]")))]
for link in links:
    driver.get(link)
    print(driver.current_url)
    driver.get(base_url)

Andersson 6 年前

我不会单击,而是获取超级引用列表,然后导航到每个页面:

links = [link.get_attribute('href') for link in driver.find_elements_by_xpath('//a[h3]')]
for link in links:
    driver.get(link)
    # Do something on the page

iamsankalp89 6 年前

python_button = driver.find_element_by_xpath(
    "//*[@id='search_results_people_search_832248975']/div[3]/div[1]/div[1]/div[2]/a/h3")
python_button.click()