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获取6中POST请求的响应

httpclient typescript angular

Souad Guo Xiuhao · 技术社区 · 6 年前

我使用angular来创建一个与API REST通信的用户界面。在下面的函数中,我首先通过post请求添加一个项目,然后在表单中添加用户输入的别名列表,然后将别名添加到项目中,然后获取所选应用程序的列表,查找它们的ID,然后将它们添加到项目中。在帖子下面:

addProject(name: string, description: string): void {

    // Ajouter un nouveau projet
    let newProjectId: number;
    let newAliasId: number;
    let url = this.baseUrl + "/projects";
    this.httpClient.post<Project>(url,
        {'name': name, 'description': description }, 
        httpOptions).subscribe((data: any) => { newProjectId = data['result']['id'];})

    // Ajouter les alias 
    for (let entry of this.aliasList) {
        let UrlAddAlias = this.baseUrl + "/alias";
        this.httpClient.post(UrlAddAlias, {'alias': entry }, httpOptions)
        .subscribe((data: any) => { newAliasId = data['result']['id'];});
        // Ajouter les alias au nouveau projet
        let UrlAliasToProject = this.baseUrl + `/projects/${newProjectId}/alias`;
        this.httpClient.post(UrlAliasToProject, {"alias_id" : newAliasId}, httpOptions)
        .subscribe((data: any) => { console.log("alias added to project");});
    };

    // Ajouter les applications selectionnÃ©es au nouveau projet
    for (let entry of this.selectedApps) {
        let Urlapp = this.baseUrl + `/apps/name/${entry}`;
        let appId;
        this.httpClient.get(Urlapp).subscribe(data => { appId = data['result']['id']; });
        let urlappToProject = this.baseUrl + `/projects/${newProjectId}/apps`;
        this.httpClient.post(urlappToProject, {'app_id': appId });
    };
}

问题是我无法检索newProjectId值和newAliasId值。我得到这个错误:

Object { headers: {â¦}, status: 405, statusText: "Method Not Allowed", url: "http://api.com/v1/projects/undefined/alias", ok: false, name: "HttpErrorResponse", message: "Http failure response for http://api.com/v1/projects/undefined/alias: 405 Method Not Allowed", error: "<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 3.2 Final//EN\">\n<title>405 Method Not Allowed</title>\n<h1>Method Not Allowed</h1>\n<p>The method is not allowed for the requested URL.</p>\n" }

我可以通过 console.log 但他们是 undefined

1 回复 | 直到 6 年前

Explosion Pills 6 年前

.subscribe 回调是异步进行的。这意味着在它之后编写的代码仍将在它之前执行。。。类似 setTimeout

setTimeout(() => console.log('second'));
console.log('first');

。订阅 内部 :

.subscribe((data: any) => {
  newProjectId = data['result']['id'];

  for (let entry of this.aliasList) { ...
});

如果可能的话,您可能还需要重新编写API,这样就不必发出多个请求,并且 post 自己处理一切。