根据页面属性显示图标

您需要从列表中的项目中获取值。从上面看,我认为这是可行的:

SPList list = SPContext.Current.Web.Lists["my list name"];
SPListItem item = list.items.GetItemById(ItemId);

//the following 2 lines are not strictly necessary
//but since you explicitly mentioned this is related to ContentTypes
//this is how you can ensure the item you retrieved is of the apprpriate type
SPContentTypeId myContentTypeId = GetContentTypeId();
if (list.ContentTypes.BestMatch(myContentTypeId).Equals(item.ContentType.Id))
{
  string value = item["interesting field name"].ToString();
  //if the value is of interest, do your thing
}

我会附和EvilgoatBob的评论吗?在这种情况下,用XSLT显示通常要容易得多。 如果这在您的情况下不合适,编码解决方案可能会起作用。 如果要在表单条目页上显示,可以尝试 custom field control

这将更容易在使用字段的任何位置一致地显示图标。

我已经知道怎么做了:

var item = SPContext.Current.File.Item; //returns the SPListItem for the current context
var myField = item["SomeFieldName"]; //this will throw a NullReferenceException if there is no data for the field yet though
Response.Write(myField.ToString());