如何在python中从一个列表生成多个列表

而不是添加原始文件的新参考/副本 numbers 到 list ,要么开始新的 列表 每当你看到 1 或添加到最新版本:

list_number = []
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 1, 11, 12, 13, 1, 21, 22, 25, 6, 1, 34, 5, 6, 7, 78]
for x in numbers:
    if x==1:
        list_number.append([1])
    else:
        list_number[-1].append(x)

print list_number

结果:

>>> for x in list_number:
...     print x
...
[1, 2, 3, 4, 5, 6, 7, 8, 9]
[1, 11, 12, 13]
[1, 21, 22, 25, 6]
[1, 34, 5, 6, 7, 78]

我的建议是2步进,首先找到索引,然后从一个打印到另一个,从最后一个打印到底:

 ones_index=[]
 numbers = [1, 2, 3,4,5,6,7,8,9, 1, 11, 12, 13, 1, 21, 22, 25, 6, 1, 34 ,5 ,6 ,7,78]
 for i,x in enumerate(numbers):
     if x==1:
         ones_index.append(i)

for i1,i in enumerate(ones_index):
     try:
         print numbers[i:ones_index[i1+1]]
    except:
         print numbers[i:]