{
"_id" : ObjectId("5b5acaf0589ff6bfb5dd091f"),
"date" : "2018/07/31",
"clock" : [
{
"time" : "10:12:02",
"values" : [
{
"name" : "A1003",
"value" : "777"
},
{
"name" : "A0001",
"value" : "888"
}
]
},
{
"time" : "13:12:02",
"values" : [
{
"name" : "A1003",
"value" : "111"
}
]
}
]
}
我可以用
$gte
$lte
getData(name: string[], fromDate: string, toDate: string): Promise<{ message: string }> {
return this._mongoUtility.testDb
.then(db => {
let collection = db.collection('TestDoc');
let fromOnlyDate = fromDate.split(' ');
let toOnlyDate = toDate.split(' ');
return collection.find({
'date': {
$gte: `${fromOnlyDate[0]}`,
$lte: `${toOnlyDate[1]}`
}
}).toArray();
})
.catch(err => {
return Promise.reject({message: 'Data not found', err: err})
})
}
我想用
time
再一次
name
并且应该显示
value
我试了很多方法,但我正在得到结果。在MongoDB中有没有其他方法可以做到这一点?敬请建议。
0:{date: "2018/07/31 10:12:02", value-A1003: "777", value-A0001: "888"}
1:{date: "2018/07/31 13:12:02", value-A1003: "111"}