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JavaScript-按两个整数属性对数组排序[重复]

sorting arrays javascript

APixel Visuals · 技术社区 · 5 年前

我有以下对象数组:

const items = [
    { name: "Different Item", amount: 100, matches: 2 },
    { name: "Different Item", amount: 100, matches: 2 },
    { name: "An Item", amount: 100, matches: 1 },
    { name: "Different Item", amount: 30, matches: 2 }
]

我要把这些分类 matches 和 amount ,因此最终结果如下:

[
    { name: "Different Item", amount: 100, matches: 2 },
    { name: "Different Item", amount: 100, matches: 2 },
    { name: "Different Item", amount: 30, matches: 2 },
    { name: "An Item", amount: 100, matches: 1 }
]

第一要务是按 比赛 ,然后在这些里面,我需要按 数量 . 我知道我可以 比赛 或者只是 数量 就像这样:

items.sort((a, b) => a.matches - b.matches);

但我怎么能两者兼顾呢?

2 回复 | 直到 5 年前

kind user Faly 5 年前

你可以用 Array#sort . 对象将首先根据 matches 然后在 amount .

const items = [
    { name: "Different Item", amount: 90, matches: 2 },
    { name: "Different Item", amount: 100, matches: 1 },
    { name: "An Item", amount: 80, matches: 1 },
    { name: "Different Item", amount: 30, matches: 2 },
    { name: "Different Item", amount: 40, matches: 1 },
    { name: "Different Item", amount: 50, matches: 1 },
    { name: "An Item", amount: 10, matches: 1 },
    { name: "Different Item", amount: 20, matches: 2 },
];

const r = [...items].sort((a, b) => b.matches - a.matches || b.amount - a.amount);

console.log(r);

Dacre Denny 5 年前

另一种基于两个临界点的排序方法 Array#sort 将是:

const items = [
    { name: "Different Item", amount: 100, matches: 2 },
    { name: "Different Item", amount: 100, matches: 2 },
    { name: "An Item", amount: 100, matches: 1 },
    { name: "Different Item", amount: 30, matches: 2 }
]

const result = items.sort((a, b) => {
  
  const matches = b.matches - a.matches;
  
  // If a.matches and b.matches are not the same,
  // sort this a and b pair based on matches in
  // descending order
  if(matches !== 0) {
    return matches;
  }
  
  // Here, the a and b pair have the same matches
  // value, so sort based on seondary criteria; 
  // amount in descending order
  return b.amount - a.amount;
});

console.log(result);