用于筛选不需要的用户名的正则表达式

你的正则表达式是 /^(?![a-zA-Z0-9]{2}_)/ {两个字母数字字符和一个下划线}”。

negative lookahead :

^(?![A-Za-z]{2}_)[A-Za-z0-9_]{3,27}$

我们来分解一下:

Assert position at the beginning of a line (at beginning of the string or after a line break character) «^»
Assert that it is impossible to match the regex below starting at this position (negative lookahead) «(?![A-Za-z]{2}_)»
   Match a single character present in the list below «[A-Za-z]{2}»
      Exactly 2 times «{2}»
      A character in the range between “A” and “Z” «A-Z»
      A character in the range between “a” and “z” «a-z»
   Match the character “_” literally «_»
Match a single character present in the list below «[A-Za-z0-9_]{3,27}»
   Between 3 and 27 times, as many times as possible, giving back as needed (greedy) «{3,27}»
   A character in the range between “A” and “Z” «A-Z»
   A character in the range between “a” and “z” «a-z»
   A character in the range between “0” and “9” «0-9»
   The character “_” «_»
Assert position at the end of a line (at the end of the string or before a line break character) «$»

只是提出一个否定的论断,比如:

/^([^A-Za-z0-9]{2}(?!\_)|[A-Za-z0-9]{3,27})/
                   ^^--Notice the assertion.

下面是一个完整的测试用例:

<?php
$names = array('SU_Coolguy','MR_Nobody','my_Pony','__SU_Coolguy','MRS_Nobody','YourPony');

foreach($names as $name){
        echo "$name => ";
        if(preg_match('/^([^A-Za-z0-9]{2}(?!\_)|[A-Za-z0-9]{3,27})/',$name)) {
                echo 'ok';
        }else{
                echo 'fail';
        }
        echo "\n";
}
?>

SU_Coolguy => fail
MR_Nobody => fail
my_Pony => fail
__SU_Coolguy => ok
MRS_Nobody => ok
YourPony => ok

在这种情况下,一个简单的方法就是将其分为大小写:用户名要么以非alpha开头,要么以alpha和非alpha开头,要么以两个alpha和非下划线开头,大致如下:

/^([^A-Za-z]|[A-Za-z][^A-Za-z]|[A-Za-z][A-Za-z][^_])/