什么是进行wiki格式化(.Net)的最佳正则表达式?

伙计们,我有一个wiki格式化算法,我正在使用 Stacked

// Body is wiki content...
string tmp = Body.Replace("&", "&amp;").Replace("<", "&lt;").Replace(">", "&gt;");
// Sanitizing carriage returns...
tmp = tmp.Replace("\\r\\n", "\\n");

// Replacing dummy links...
tmp = Regex.Replace(
" " + tmp,
"(?<spaceChar>\\s+)(?<linkType>http://|https://)(?<link>\\S+)",
"${spaceChar}<a href=\"${linkType}${link}\"" + nofollow + ">${link}</a>",
RegexOptions.Compiled).Trim();

// Replacing wiki links
tmp = Regex.Replace(tmp,
"(?<begin>\\[{1})(?<linkType>http://|https://)(?<link>\\S+)\\s+(?<content>[^\\]]+)(?<end>[\\]]{1})",
"<a href=\"${linkType}${link}\"" + nofollow + ">${content}</a>",
RegexOptions.Compiled);

// Replacing bolds
tmp = Regex.Replace(tmp,
"(?<begin>\\*{1})(?<content>.+?)(?<end>\\*{1})",
"<strong>${content}</strong>",
RegexOptions.Compiled);

// Replacing italics
tmp = Regex.Replace(tmp,
"(?<begin>_{1})(?<content>.+?)(?<end>_{1})",
"<em>${content}</em>",
RegexOptions.Compiled);

// Replacing lists
tmp = Regex.Replace(tmp,
"(?<begin>\\*{1}[ ]{1})(?<content>.+)(?<end>[^*])",
"<li>${content}</li>",
RegexOptions.Compiled);
tmp = Regex.Replace(tmp,
"(?<content>\\<li\\>{1}.+\\<\\/li\\>)",
"<ul>${content}</ul>",
RegexOptions.Compiled);

// Quoting
tmp = Regex.Replace(tmp,
"(?<content>^&gt;.+$)",
"<blockquote>${content}</blockquote>",
RegexOptions.Compiled | RegexOptions.Multiline).Replace("</blockquote>\n<blockquote>", "\n");

// Paragraphs
tmp = Regex.Replace(tmp,
"(?<content>)\\n{2}",
"${content}</p><p>",
RegexOptions.Compiled);

// Breaks
tmp = Regex.Replace(tmp,
"(?<content>)\\n{1}",
"${content}<br />",
RegexOptions.Compiled);

// Code
tmp = Regex.Replace(tmp,
"(?<begin>\\[code\\])(?<content>[^$]+)(?<end>\\[/code\\])",
"<pre class=\"code\">${content}</pre>",
RegexOptions.Compiled);

// Now hopefully tmp will contain perfect HTML

对于那些认为在这里很难看到代码的人,您也可以查看它 here ...

下面是完整的“wiki语法”;

Link; [http://x.com text]

*bold* (asterisk on both sides)

_italic_ (underscores on both sides)

* Listitem 1
* Listitem 2
* Listitem 3
(the above is asterixes but so.com also creates lists from it)

2 x Carriage Return is opening a new paragraph

1 x Carriage Return is break (br)

[code]
if( YouDoThis )
  YouCanWriteCode();
[/code]


> quote (less then operator)