如何从MongoDB集合创建JSON提要

    $cursor = $this->collection->find($params);
    $return = array();
    $i=0;
    while( $cursor->hasNext() )
    {

        $return[$i] = $cursor->getNext();
        // key() function returns the records '_id'
        $return[$i++]['_id'] = $cursor->key();
    }
    return json_encode($return);

我就是这样从Mongo返回JSON的。

我是这样做的:

$cursor = $collection->find($params);
if($cursor->hasNext())
{
    return json_encode(iterator_to_array($cursor));
}

如果您需要\u id,请检查此答案以了解为什么您没有获得它们: MongoDB PHP: How do I get ObjectId with a JSON feed? (it's blank)

我就是这么做的:

$data = json_decode(json_encode(iterator_to_array($cursor, true)));

foreach($data as $doc){
    echo 'title:'.$doc->title.'<br>';   
}