将Objective-C中的NSRange转换为Swift

如果您使用 String ,你可以参考 endIndex :

let searchString: String = "Apple_HFS "
if let range: Range<String.Index> = tempString.rangeOfString(searchString) {
    let index = range.endIndex
    let stringAfter = tempString.substringFromIndex(index)
    // do something with `stringAfter`
} else {
    // not found
}

我包括了这些类型,这样你就可以看到发生了什么,但通常我只会写:

let searchString = "Apple_HFS "
if let range = tempString.rangeOfString(searchString) {
    let stringAfter = tempString.substringFromIndex(range.endIndex)
    // do something with `stringAfter`
} else {
    // not found
}

这就是你要找的吗?

var str : NSString = "A string that include the searched string Apple_HFS inside"

let searchString : NSString = "Apple_HFS "
let range : NSRange = str.rangeOfString(searchString) // (42, 10)
let idx : Int = range.location + range.length // 52

演示: http://swiftstub.com/831969865/

简单的解决方案 不使用任何对象方法或类型:

假设您有:

let nsrange = NSRange(location: 3, length: 5)
let string = "My string"

现在你需要转换 NSRange 到 Range :

let range = Range(start: advance(string.startIndex, nsrange.location), end: advance(string.startIndex, nsrange.location + nsrange.length))