当WebView:ShouldStartLoadWithRequest:NavigationType:返回false时取消选择突出显示的链接

我在uiwebview中显示一些带有链接的HTML。我希望在用户确认链接应该真正打开后,在Safari中打开链接。

打开链接可以正常工作,但如果用户取消,链接将保持选中状态,并以蓝色突出显示。如何取消选择链接并去掉突出显示?

- (BOOL)webView:(UIWebView *)aWebView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {
 if (navigationType == UIWebViewNavigationTypeLinkClicked) {
  self.url = request.URL;
  UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Open the Link in Safari" message:[request.URL absoluteString] delegate:self cancelButtonTitle:@"Cancel" otherButtonTitles:@"OK"];
  [alert show];
  [alert release];
        return false;
    }
    return true;
}

- (void)alertView:(UIAlertView *)alertView didDismissWithButtonIndex:(NSInteger)buttonIndex {
 if (buttonIndex == 1) {
        [[UIApplication sharedApplication] openURL:url];
 }
 // Insert magic deselection code here
}

更新: 似乎[uiWebView StringByEvaluingJavaScriptfromString:]但具体情况如何?我试过

for (var e in document.getElementsByTag("a")) {e.blur();}

但无济于事。