将数组传递给函数参数并从嵌套数组中获取值

我在练习信用卡检查机的时候被卡住了。

// All valid credit card numbers
const valid1 = [4, 5, 3, 9, 6, 7, 7, 9, 0, 8, 0, 1, 6, 8, 0, 8]
const valid2 = [5, 5, 3, 5, 7, 6, 6, 7, 6, 8, 7, 5, 1, 4, 3, 9]
const valid3 = [3, 7, 1, 6, 1, 2, 0, 1, 9, 9, 8, 5, 2, 3, 6]
const valid4 = [6, 0, 1, 1, 1, 4, 4, 3, 4, 0, 6, 8, 2, 9, 0, 5]
const valid5 = [4, 5, 3, 9, 4, 0, 4, 9, 6, 7, 8, 6, 9, 6, 6, 6]

// All invalid credit card numbers
const invalid1 = [4, 5, 3, 2, 7, 7, 8, 7, 7, 1, 0, 9, 1, 7, 9, 5]
const invalid2 = [5, 7, 9, 5, 5, 9, 3, 3, 9, 2, 1, 3, 4, 6, 4, 3]
const invalid3 = [3, 7, 5, 7, 9, 6, 0, 8, 4, 4, 5, 9, 9, 1, 4]
const invalid4 = [6, 0, 1, 1, 1, 2, 7, 9, 6, 1, 7, 7, 7, 9, 3, 5]
const invalid5 = [5, 3, 8, 2, 0, 1, 9, 7, 7, 2, 8, 8, 3, 8, 5, 4]

// Can be either valid or invalid
const mystery1 = [3, 4, 4, 8, 0, 1, 9, 6, 8, 3, 0, 5, 4, 1, 4]
const mystery2 = [5, 4, 6, 6, 1, 0, 0, 8, 6, 1, 6, 2, 0, 2, 3, 9]
const mystery3 = [6, 0, 1, 1, 3, 7, 7, 0, 2, 0, 9, 6, 2, 6, 5, 6, 2, 0, 3]
const mystery4 = [4, 9, 2, 9, 8, 7, 7, 1, 6, 9, 2, 1, 7, 0, 9, 3]
const mystery5 = [4, 9, 1, 3, 5, 4, 0, 4, 6, 3, 0, 7, 2, 5, 2, 3]

// An array of all the arrays above
const batch = [valid1, valid2, valid3, valid4, valid5, invalid1, invalid2, invalid3, invalid4, invalid5, mystery1, mystery2, mystery3, mystery4, mystery5]


// Add your functions below:
const validateCred = (array)=> {
  let tempArrSub = []; //Holds values of the 9 subtracted from doubled elements bigger than 9
  let tempArr = array; //Copies the values of the array passed into parameters
  tempArr.pop();
  tempArr.reverse();

  for (let i = tempArr.length-1; i >=0; i-=2){ //Doubles every two elements from right to left
    tempArr[i] *= 2;
  }

  for (let k = 0; k < tempArr.length; k++) { //Subtract 9 from every second element (right to left) if bigger than 9
    if (tempArr[k] > 9){
      tempArrSub.push(tempArr[k] - 9);
    }
    else {
      tempArrSub.push(tempArr[k]);
    }
  }

  let tempArrSum = 0;

  for (let m = 0; m < tempArrSub.length; m++){ //Calculates the sum of all elements in the array
    tempArrSum += tempArrSub[m];
  }

  tempArrSum += array.pop(); //Adds the last digit of initial array to the sum

  if (tempArrSum % 10 === 0) { //Returns true if the sum is divisible by 10
    return true;
  }
  else {
    return false;
  }

} //End Of Function


const findInvalidCards = (nestedArray) => {
  let invalidCards = [];
  let validCards = [];
  for (let a = 0; a < nestedArray.length; a++){

    if ( validateCred(nestedArray[a]) == true ) {
      validCards.push(nestedArray[a]);
    }
    else {
      invalidCards.push(nestedArray[a]);
    }
  }

  console.log("Invalid cards: \n" + invalidCards);
  console.log("Valid cards: \n" + validCards);
}

我逐个检查了作为validateCred()函数参数的所有数组。它是有效的,并返回每一张信用卡的真或假。

为了自动化这个过程,我希望findInvalidCards()通过在其内部调用validateCred()函数并为每个卡返回布尔值来查找有效或无效的卡。

我被卡住了。因为它对第一张卡返回true,对其余的卡返回false。我玩了一整天的代码,但是我不能前进。我依靠你的帮助。提前谢谢