代码之家 › 专栏 › 技术社区 › C. Cunanan

int函数返回ASCII特殊字符?

int c

C. Cunanan · 技术社区 · 7 年前

所以我是C语言的新手,我有一个程序可以询问电话号码

getInt函数如下所示:

int getInt(void) {
    int num;
    char newline = 0;
    do {
        scanf("%d%c", &num, &newline);
        if (newline != '\n') {
            printf("*** Invalid Integer *** <Please enter an integer>: ");
            clearKeyboard();
        }
    } while (newline != '\n');
    return num;
}

定义如下:

void getNumber(struct Number *num) {
    int response;

    printf("Please enter the contact's cell phone number: ");
    *num->cell = getInt();

    printf("Do you want to enter a home phone number? (y or n): ");
    response = yes();

    if (response == 1) {
        printf("Please enter the contact's home phone number: ");
        *num->home = getInt();
    }

    printf("Do you want to enter a business phone number? (y or n): ");
    response = yes();

    if (response == 1) {
        printf("Please enter the contact's business phone number: ");
        *num->business = getInt();
    }
}

主要内容如下:

printf("Numbers: %s|%s|%s\n", contact.number.cell, contact.number.home, contact.number.business);

但出于某种原因,当我输入电话号码时,输出如下: error ascii?

抱歉,我知道图像中的文本,但我无法从调试窗口复制粘贴。

我只想知道我的代码中可能有什么错误,它会返回ascii字母。提前谢谢你

1 回复 | 直到 7 年前

C. Cunanan 7 年前

好的,在看了@Pablo评论的类似问题后,它现在起作用了。答案中有以下代码:

void getNumbers(struct Numbers *numbers) // getNumbers function definition
{
    int result;

    printf("Please enter the contact's cell phone number: ");
    scanf("%s", numbers->cell);
    clear_buffer(stdin);


    if(yes("Do you want to enter a home phone number? (y or n)"))
    {
        printf("Please enter the contact's home phone number: ");
        scanf("%s", numbers->home);
        clear_buffer(stdin);
    }

    if(yes("Do you want to enter a business phone number? (y or n)"))
    {
        printf("Please enter the contact's business phone number: ");
        scanf("%s", numbers->business);
        clear_buffer(stdin);
    }
}

于是我继续复制同样的想法:

void getNumber(struct Number *num) {
    int response;
    printf("Please enter the contact's cell phone number: ");
    scanf("%10s", num->cell); // I changed this line from:
//  *num->cell = getInt();


    printf("Do you want to enter a home phone number? (y or n): ");
    response = yes();

    if (response == 1) {
        printf("Please enter the contact's home phone number: ");
        scanf("%10s", num->home); // I changed this line from:
//  *num->home = getInt();
    }

    printf("Do you want to enter a business phone number? (y or n): ");
    response = yes();

    if (response == 1) {
        printf("Please enter the contact's business phone number: ");
        scanf("%10s", num->business); // I changed this line from:
//  *num->business = getInt();
    }
}

可能getInt函数不适合定义。我不知道该如何解释,但这是可行的。

谢谢大家。