article
. 如果任务和列是复杂的类型,你也会在那里找到如何映射它们。通常必须使用MapHiearchy和Case方法,而不是mapsingeltype。
编辑:
以下是示例:
using System;
using System.Collections.Generic;
using System.Data.Entity;
using System.Data.Entity.ModelConfiguration;
namespace EFTest
{
public class RequestBase
{
public int Id { get; set; }
public DateTime? RequestedDate { get; set; }
public int UserId { get; set; }
}
public class Mission
{
public int Id { get; set; }
public string Name { get; set; }
public virtual ICollection<MissionRequest> MissionRequests { get; set; }
}
public class Column
{
public string Name { get; set; }
}
public class MissionRequest : RequestBase
{
public virtual Mission Mission { get; set; }
}
public class ShiftRequest : RequestBase
{
public Column Column { get; set; }
}
public class TestContext : DbContext
{
public DbSet<RequestBase> Requests { get; set; }
public DbSet<Mission> Missions { get; set; }
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.ContainerName = "EFTest";
modelBuilder.IncludeMetadataInDatabase = false;
// Example of complex type mapping. First you have to define
// complex type. Than you can access type properties in
// MapHiearchy.
var columnType = modelBuilder.ComplexType<Column>();
columnType.Property(c => c.Name).HasMaxLength(50);
modelBuilder.Entity<Mission>()
.Property(m => m.Id)
.IsIdentity();
modelBuilder.Entity<Mission>()
.HasKey(m => m.Id)
.MapSingleType(m => new { m.Id, m.Name })
.ToTable("dbo.Missions");
modelBuilder.Entity<RequestBase>()
.Property(r => r.Id)
.IsIdentity();
// You map multiple entities to single table. You have to
// add some discriminator to differ entity type in the table.
modelBuilder.Entity<RequestBase>()
.HasKey(r => r.Id)
.MapHierarchy()
.Case<RequestBase>(r => new { r.Id, r.RequestedDate, r.UserId, Discriminator = 0 })
.Case<MissionRequest>(m => new { MissionId = m.Mission.Id, Discriminator = 1 })
.Case<ShiftRequest>(s => new { ColumnName = s.Column.Name, Discriminator = 2 })
.ToTable("dbo.Requests");
}
}
}
我更新了这个例子。现在任务是实体而不是复杂类型。