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创建新的a thread()正在将参数化的threadstart对象作为c sharp中的参数进行请求

FosterZ · 技术社区 · 14 年前

啊,我对线程编程非常熟悉,刚开始创建多个线程的基本步骤,所以我在谷歌上搜索并获得了一些关于在C中创建线程的片段,以下是我发现的片段:

public MyThread(string name) { 
    count = 0; 
    thrd = new Thread(new ThreadStart(this.run)); // here m getting error
    thrd.Name = name; 
    thrd.Start(); 
  } 

  // Entry point of thread. 
  void run() { 
    Console.WriteLine(thrd.Name + " starting."); 

    do { 
      Thread.Sleep(500); 
      Console.WriteLine("In " + thrd.Name + 
                        ", count is " + count); 
      count++; 
    } while(count < 10); 

    Console.WriteLine(thrd.Name + " terminating."); 
  } 
}

错误是 与System.Threading.Thread.Thread(System.Threading.ParameterizedThreadStart)匹配的最佳重载方法具有一些无效参数

为什么线程构造函数要求我提供参数化的threadstart对象,我希望传递简单的threadstart对象。

另一件事是threadstart类没有带1个参数的构造函数,即它需要0个参数,但在代码片段中,它们显示了 new ThreadStart(this.run) 这个? M使用Cα2008

这是完整的代码

using System; 
using System.Threading; 

class MyThread { 
  public int count; 
  public Thread thrd; 

  public MyThread(string name) { 
    count = 0; 
    thrd = new Thread(new ThreadStart(this.run)); 
    thrd.Name = name; 
    thrd.Start(); 
  } 

  // Entry point of thread. 
  void run() { 
    Console.WriteLine(thrd.Name + " starting."); 

    do { 
      Thread.Sleep(500); 
      Console.WriteLine("In " + thrd.Name + 
                        ", count is " + count); 
      count++; 
    } while(count

3 回复 | 直到 14 年前

Thomas Levesque 14 年前

不知道为什么它不起作用,但你可以尝试一下:

thrd = new Thread(run);

转换自 run 方法组到 ThreadStart 委托是隐式的。

我怀疑你之间有名字冲突 System.Threading.ThreadStart 以及在代码中其他地方定义的另一个类型…尝试插入插入符号 委托 按F12进入申报

Dennis 14 年前

我已经完成了您给出的不完整的示例,并且没有遇到相同的编译器错误。

class Program
{
    static int count;
    static Thread thrd;


    public static void MyThread(string name) { 
        count = 0; 
        thrd = new Thread(new ThreadStart(run)); // here m getting error
        thrd.Name = name; 
        thrd.Start(); 
    } 

  // Entry point of thread. 
  static void  run() { 
    Console.WriteLine(thrd.Name + " starting.");

    do
    {
        Thread.Sleep(500);
        Console.WriteLine("In " + thrd.Name +
                          ", count is " + count);
        count++;
    } while (count == 5);
  }



  static void Main(string[] args)
  {
  }
}

Jon Skeet 14 年前

那应该很好,因为是 an overload 拿 ThreadStart 而不是 ParameterizedThreadStart .

我怀疑这里还有别的东西在玩…你能提供一个短的但是完成演示问题的示例?

除了缺少类声明本身和变量声明之外,您的代码还为我编译,没有问题:

using System;
using System.Threading;

class MyThread {

    int count;
    Thread thrd;

    public MyThread(string name) { 
        count = 0; 
        thrd = new Thread(new ThreadStart(this.run)); // here m getting error
        thrd.Name = name; 
        thrd.Start(); 
    } 

    // Entry point of thread. 
    void run() { 
        Console.WriteLine(thrd.Name + " starting."); 

        do { 
            Thread.Sleep(500); 
            Console.WriteLine("In " + thrd.Name + 
                              ", count is " + count); 
            count++; 
        } while(count < 10); 

        Console.WriteLine(thrd.Name + " terminating."); 
    } 
}