1:20
按升序排列,按降序排列的行基于
out.tot
# Generate data
shooter1 <- round(runif(n = 20, min = 1, max = 10))
shooter2 <- round(runif(n = 20, min = 1, max = 10))
shooter3 <- round(runif(n = 20, min = 1, max = 10))
out <- data.frame(t(data.frame(shooter1, shooter2, shooter3)))
colnames(out) <- 1:ncol(out)
out.sort <- t(apply(out, 1, sort, na.last = FALSE))
out.tot <- apply(out , 1, sum)
colnames(out.sort) <- 1:ncol(out.sort)
out2 <- cbind(out.sort, out.tot)
out3 <- apply(out2, 2, sort, decreasing = TRUE, na.last = FALSE)
out2
在
out3
失去了他们。唯一的区别是我用
MARGIN = 2
产出3
不会消失?
> out2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 out.tot
shooter1 1 2 2 3 3 3 4 5 5 5 6 6 6 6 6 7 8 9 9 10 106
shooter2 1 3 3 3 3 4 4 4 5 5 5 5 5 6 7 8 8 9 9 10 107
shooter3 1 1 2 2 2 3 3 4 5 5 5 6 6 6 6 7 8 8 8 9 97
> out3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 out.tot
[1,] 1 3 3 3 3 4 4 5 5 5 6 6 6 6 7 8 8 9 9 10 107
[2,] 1 2 2 3 3 3 4 4 5 5 5 6 6 6 6 7 8 9 9 10 106
[3,] 1 1 2 2 2 3 3 4 5 5 5 5 5 6 6 7 8 8 8 9 97