代码之家 › 专栏 › 技术社区 › Connell.O'Donnell

带有React Typescript的Spread运算符

react-tsx typescript reactjs

Connell.O'Donnell · 技术社区 · 6 年前

const PrivateRoute = ({ component: Component, ...rest }) => (
<Route {...rest} render={(props) => (
    Acc.isLoggedIn === true
        ? <Component {...props} />
        : <Redirect to={{
            pathname: '/login',
            state: { from: props.location }
        }} />
)} />

)

export { PrivateRoute };

我想把它更新成这样

interface IPrivateRouteProps {
}

interface IPrivateRouteState {
  isAuthenticated?: boolean
}

export class PrivateRoute extends React.Component<IPrivateRouteProps, IPrivateRouteState> {
constructor(props: IPrivateRouteProps) {
    super(props);

    this.state = ({ isAuthenticated: null });
}

componentDidMount() {
    Acc.isAuthenticated()
        .then(isAuthenticated => {
            this.setState({ isAuthenticated: isAuthenticated });
        });
}

render() {
    if (this.state.isAuthenticated == null) {
        return null;
    }
    else if (this.state.isAuthenticated) {
        return <Route {...rest} render={(props) => (<Component {...props} />)}/>
    }
    else {
        return <Route {...rest} render={(props) => (<Redirect to={{ pathname: '/login', state: { from: props.location } }} />)}/>
    }
}
}

如何使用typescript中的spread运算符传递道具?

不用说,我不仅仅依赖客户端代码进行身份验证。

我已经试过了,但没用: Spreading react props in tsx in typescript 2.3.1