x8086组件,将0.0001推到堆栈上成为9.99999。。而不是0.0001

我正在尝试实现平方根的牛顿算法。我已经包括了完整的C程序,所以你可以看到我正在尝试做什么。我正在尝试编写汇编中包含的C程序。现在我只是想正确地编写while循环。我使用命令将0.0001推到堆栈上 fld accuracy .下面是我的注册表截图。ST0应为0.0001,但应为9.999。如何更正此值,以便与0.0001(而不是9.999)进行比较。。?

.586
.MODEL FLAT
.STACK 4096                 
.data
    PUBLIC _newton
upper REAL4 9.0
accuracy REAL4 0.00001
lower REAL4 1.0
.code

_newton  PROC

        finit   ;initialize fpu
        fld upper
        fld lower
        fsub
        fld accuracy
        fcom
        ;if less than call code for the rest of the algorithm.
        mov eax, 0
        ret

_newton ENDP
END

我正在实现的算法的C版本:

double sqrtX (double x)
{
    const double ACCURACY=0.00001;
    double lower, upper, guess;
    double number;

    number = x;
    lower = 1;
    upper = number;

    while ((upper-lower) > ACCURACY)
    {
        guess = (lower + upper) / 2;
        if((guess * guess) > number)
        {
            upper = guess;
        }
        else
        {
            lower = guess;
        }
    }
    return (lower + upper)/2;
}