将多行字符串转换为单行

我试过了 \n 它是有效的

scala> val myString = """
     | a=b
     | c=d
     | """.stripMargin
myString: String =
"
a=b
c=d
"

scala> myString.replaceAll("\n",";")
res0: String = ;a=b;c=d;

scala> res0.substring(1, myString.length)
res1: String = a=b;c=d;

我希望有帮助

https://stackoverflow.com/a/25652402/5205022

"""
  |a=b
  |c=d
  |""".stripMargin.linesIterator.mkString(";").trim

;a=b;c=d

或使用单个空格 " " as分离器

"""
  |Live long
  |and
  |prosper!
  |""".stripMargin.linesIterator.mkString(" ").trim

Live long and prosper!

因为这是谷歌在“Scala multiline to a single line”上的第一个结果,这个问题相当普遍。添加一种隐含方式可能是合理的:

implicit class StringExtensionImplicits(s: String) {

    def singleLine: String = {
      singleLine('|')
    }

    def singleLine(marginChar: Char): String = {
      s.stripMargin(marginChar).replace('\n', ' ')
    }

}

现在您可以:

logger.info(
  """I'm a so long log entry that some devs who like vim don't like me.
    |But you can help them to keep patience.""".singleLine)

试试这个

myString.split("\n").filter(_.nonEmpty).mkString("",";",";")

val myString = "This is " +
               "my string"

哪个输出是 This is my string . 您也可以在这里使用s字符串来实现变量