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在浏览器中响应本机开放链接并返回应用程序

react-native reactjs javascript

Mort Raphael Souza · 技术社区 · 6 年前

我在React Native中开发了一个应用程序,它应该与支付网关通信,在完成支付过程(成功或失败)后,我需要向用户显示一个警报。为此,我在 WebView 然后我得到返回的URL onNavigationStateChange 并显示成功或失败消息。

但是,这种流动安全问题必须在 默认设备浏览器 .

当前代码:

const BASEURL = 'https://gatewayURL/?ID=';
let Token = null;
let paymentAccepted = null;
let paymentFactorId = null;

class Gateway extends PureComponent {
  static propTypes = {
    dispatch: PropTypes.func,
    navigation: PropTypes.any,
  }

  componentWillMount() {
    this.props.dispatch(getPaymentStatus());
  }


  _onLoad(webViewState) {
    let url = webViewState.url.toString();
    let isResponseValid = url.includes('backFromGateway');
    if(isResponseValid){
      if(this.props.checkedPaymentStatus != 'checked' ){
        setTimeout(() => {
          this.props.dispatch(setPaymentStatus('checked'));

          let splitedURL = url.split("/");
          paymentFactorId = splitedURL[splitedURL.length -2];
          if(splitedURL[splitedURL.length - 1] === '0'){
            paymentAccepted = true;
            this.props.dispatch(setGatewayResponse('done', paymentFactorId));
          }
          else {
            paymentAccepted = false;
            this.props.dispatch(setGatewayResponse('rejected', paymentFactorId));
          }


          this.props.navigation.navigate('BackFromGateway', { title: '' })
        }, 1000);
      }
    }
  }


  render() {
    const { addNewOrderGatewayToken, checkedPaymentStatus } = this.props;
    token = addNewOrderGatewayToken;
    let view = null;
    if(checkedPaymentStatus !== 'checked'){
      view =  <WebView onNavigationStateChange={this._onLoad.bind(this)} style={styles.container} source={{ uri: `${BASEURL}${token}`  }}/>
    }
    else{
      view = <View></View>
    }

    return (
      <View style={styles.container}>
        {view}
      </View>      
    );
  }
}

知道吗?
谢谢

2 回复 | 直到 6 年前

blaz 6 年前

here gatewaylistener

gatewaylistener://success?id={paymentId} gatewaylistener://error?id={paymentId}

// setup
componentDidMount() {
  Linking.getInitialURL().then((url) => {
    if (url) {
      this.handleOpenURL(url)
    }
  }).catch(err => {})
  Linking.addEventListener('url', this.handleOpenURL)
}

componentWillUnmount() {
  Linking.removeEventListener('url', this.handleOpenURL)
}

// open your gateway
async openGateWay = () => {
  const { addNewOrderGatewayToken } = this.props
  const url = `${BASEURL}${addNewOrderGatewayToken}`
  const canOpen = await Linking.canOpenURL(url)
  if (canOpen) {
    this.props.dispatch(setPaymentStatus('checked'))
    Linking.openURL(url)
  }
}

// handle gateway callbacks
handleOpenURL = (url) => {
  if (isSucceedPayment(url)) { // your condition
    // handle success payment
  } else {
    // handle failure
  }
}

jdnichollsc 5 年前

InAppBrowser

  getDeepLink (path = '') {
    const scheme = 'my-demo'
    const prefix = Platform.OS === 'android' ? `${scheme}://demo/` : `${scheme}://`
    return prefix + path
  }

  async tryDeepLinking () {
    const redirectToURL = `https://proyecto26.github.io/react-native-inappbrowser/`
    const redirectUrl = this.getDeepLink('home')
    const url = `${redirectToURL}?redirect_url=${encodeURIComponent(redirectUrl)}`
    try {
      if (await InAppBrowser.isAvailable()) {
        const result = await InAppBrowser.openAuth(url, redirectUrl)
        await this.sleep(800)
        Alert.alert('Response', JSON.stringify(result))
      } else {
        // You can use Linking directly for iOS < 9
      }
    } catch (error) {
      Alert.alert('Somethingâs wrong with the app :(')
    }
  }