WeakReference的get方法返回的强引用是否会导致AsyncTask onProgressUpdate中出现内存泄漏?

我想使用 WeakReference 避免内存泄漏 AsyncTask 。我在网上找到的示例仅使用 get() 中的方法 onPostExecute ,但我也想用它来更新进度。现在我想知道 get 方法本身会导致内存泄漏吗?

private static class ExampleAsyncTask extends AsyncTask<Integer, Integer, String> {
    private WeakReference<MainActivity> activityReference;

    ExampleAsyncTask(MainActivity context) {
        activityReference = new WeakReference<>(context);
    }

    @Override
    protected void onPreExecute() {
        super.onPreExecute();

        MainActivity activity = activityReference.get();
        if (activityReference.get() == null) {
            return;
        }

        activity.progressBar.setVisibility(View.VISIBLE);
    }

    @Override
    protected String doInBackground(Integer... integers) {
        Log.i("TAG", "doInBackground started");
        for (int i = 1; i < integers[0]; i++) {
            try {
                Thread.sleep(1000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }

            publishProgress((i * 100) / integers[0]);
        }

        return "Finished";
    }

    @Override
    protected void onProgressUpdate(Integer... values) {
        super.onProgressUpdate(values);

        MainActivity activity = activityReference.get();
        if (activity == null || activity.isFinishing()) {
            return;
        }

        activity.progressBar.setProgress(values[0]);
    }

    @Override
    protected void onPostExecute(String s) {
        super.onPostExecute(s);

        MainActivity activity = activityReference.get();
        if (activity == null || activity.isFinishing()) {
            return;
        }

        activity.progressBar.setProgress(0);
        activity.progressBar.setVisibility(View.INVISIBLE);
        Toast.makeText(activity, s, Toast.LENGTH_SHORT).show();
    }
}