laravel Eloquent ORM delete()方法

我认为您可以更改查询,然后像这样尝试:

$res=User::where('id',$id)->delete();

之前 delete laravel中有几种方法。

User::find(1) User::first() 返回实例。

User::where('id',1)->get 和 User::all() 返回实例的集合。

呼叫 true/false

$user=User::find(1);
$user->delete(); //returns true/false

呼叫 删去

//assume you have 10 users, id from 1 to 10;
$result=User::where('id','<',11)->delete(); //returns 11 (the number of the records had been deleted)

//lets call delete again
$result2=User::where('id','<',11)->delete(); //returns 0 (we have already delete the id<11 users, so this time we delete nothing, the result should be the number of the records had been deleted(0)  ) 

还有其他删除方法,您可以调用 destroy

$result=User::destroy(1,2,3);
$result=User::destroy([1,2,3]);
$result=User::destroy(collect([1, 2, 3]));
//these 3 statement do the same thing, delete id =1,2,3 users, returns the number of the records had been deleted

如果你是新手,还有一件事 laravel ,您可以使用 php artisan tinker dd($result) , print_r($result);

一开始

你应该知道 destroy() delete()

在您的情况下,您并没有检查数据库中是否存在记录。记录只有在存在时才能删除。

$user = User::find($id);
    if($user){
        $destroy = User::destroy(2);
    }

价值或 $destroy $data 类似阵列:

if ($destroy){

    $data=[
        'status'=>'1',
        'msg'=>'success'
    ];

}else{

    $data=[
        'status'=>'0',
        'msg'=>'fail'
    ];

}

希望,你明白。

雄辩的提供 destroy() 返回的函数 boolean 价值如果有记录 存在 在数据库和 你会得到 true 否则 false .

Laravel Tinker外壳

在这种情况下,您的代码应该如下所示:

public function destroy($id)
    {
        $res = User::destroy($id);
        if ($res) {
            return response()->json([
                'status' => 1,
                'msg' => 'success'
            ]);
        } else {
            return response()->json([
                'status' => 0,
                'msg' => 'fail'
            ]);
        }
    }

有关的更多信息 Laravel Eloquent Deleting Models

$model=User::where('id',$id)->delete();

$user=User::find($request->id);
  
   if($user)
   {
   // return $user;           <------------------------user exist
       if($user->delete()){
         return 'user deleted';
         }
    else{
       return "something wrong";
        }   

   }
  else{
     return "user not exist";// <--------------------user not exist
    }

首先,使用 第二,使用 哪里 你可以试试这样的。 第一:

User::find($id)->destroy();

User::where('id', $id)->delete();

现在请尝试,它将返回真/假结果。