数组中项目的顺序与来自的列主顺序不匹配
meshgrid
.你已经差不多完成了,但是你需要用不同的形状重塑你的1D数组,然后将结果转换回你需要的实际形状:
N = 5;
[xf,yf,zf,vf] = flow(N);
ux = unique(xf);
uy = unique(yf);
uz = unique(zf);
x = nan(numel(xf),1);
y = nan(numel(yf),1);
z = nan(numel(zf),1);
v = nan(numel(vf),1);
iCount = 1;
for iX = 1:numel(ux)
for iY = 1:numel(uy)
for iZ = 1:numel(uz)
x(iCount) = ux(iX);
y(iCount) = uy(iY);
z(iCount) = uz(iZ);
v(iCount) = vf((xf == x(iCount))&(yf == y(iCount))&(zf == z(iCount)));
iCount = iCount+1;
end
end
end
% new stuff starts here
X = permute(reshape(x,[N,N,2*N]),[2,3,1]);
Y = permute(reshape(y,[N,N,2*N]),[2,3,1]);
Z = permute(reshape(z,[N,N,2*N]),[2,3,1]);
V = permute(reshape(v,[N,N,2*N]),[2,3,1]);
% check equivalence
isequal(X,xf)
isequal(Y,yf)
isequal(Z,zf)
isequal(V,vf)
上面的内容表明输入数组被复制(我们得到了四个逻辑数组
1
S)。
注意,您的测试用例应该更加不对称,因为现在一些输入数组是彼此的转置,并且三维中的两个具有相同的大小。如果你的测试尺寸不对称,即
[N,M,K]
,更容易找出可能的歧义,因为在这种情况下,所有维度都是不等价的:
N = 2; M = 3; K = 4;
[xf,yf,zf] = meshgrid(1:N,1:M,1:K);
vf = flow(xf,yf,zf);
ux = unique(xf);
uy = unique(yf);
uz = unique(zf);
x = nan(numel(xf),1);
y = nan(numel(yf),1);
z = nan(numel(zf),1);
v = nan(numel(vf),1);
iCount = 1;
for iX = 1:numel(ux)
for iY = 1:numel(uy)
for iZ = 1:numel(uz)
x(iCount) = ux(iX);
y(iCount) = uy(iY);
z(iCount) = uz(iZ);
v(iCount) = vf((xf == x(iCount))&(yf == y(iCount))&(zf == z(iCount)));
iCount = iCount+1;
end
end
end
X = permute(reshape(x,[K,M,N]),[2,3,1]);
Y = permute(reshape(y,[K,M,N]),[2,3,1]);
Z = permute(reshape(z,[K,M,N]),[2,3,1]);
V = permute(reshape(v,[K,M,N]),[2,3,1]);
% check equivalence
isequal(X,xf)
isequal(Y,yf)
isequal(Z,zf)
isequal(V,vf)