bash脚本执行日期/时间

写一个函数。使用 date +"%k" 获取当前时间,以及 (( )) 比较一下。

基本回答:

case "$1" in
(-force)
    : OK;;
(*)
    case $(date +'%H') in
    (09|1[0-6]) 
        echo "Cannot run between 09:00 and 17:00" 1>&2
        exit 1;;
    esac;;
esac

请注意,我通过运行以下命令测试了这一点(一个名为“so.sh”的脚本):

TZ=US/Pacific sh so.sh
TZ=US/Central sh so.sh

它在太平洋时间(08:50)工作,而不是在中部时间(10:50)。有关这一点的重点是,您的控件只和环境变量一样好。用户可以使用环境变量进行futz。

这作品

#!/bin/bash

# Ensure environmental variable runprogram=yes isn't set before 
unset runprogram 

# logic works out to don't run if between 9 and 5pm as you requested
[ $(date "+%k")  -le 9 -a  $(date +"%k")  -ge 17 ] && runprogram=yes  

# Adding - avoids the need to test if the length of $1 is zero
[ "${$1}-" = "-forced-" ] && runprogram=yes 

if [ "${runprogram}-" = "yes-" ]; then 
    run_program 
else 
    echo "No Go" 1>&2 #redirects message to standard error
fi

测试脚本:

#!/bin/bash

HOUR=$(date +%k)
echo "Now hour is $HOUR"

if [[ $HOUR -gt 9 ]] ; then
  echo 'after 9'
fi


if [[ $HOUR -lt 23 ]]; then
  echo 'before 11 pm'
fi