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R插入符号中随机森林的混淆矩阵

confusion-matrix r-caret random-forest r

Mike · 技术社区 · 7 年前

我有二进制YES/NO类响应的数据。使用以下代码运行RF模型。我在获取混淆矩阵结果时遇到问题。

 dataR <- read_excel("*:/*.xlsx")
 Train    <- createDataPartition(dataR$Class, p=0.7, list=FALSE)  
 training <- dataR[ Train, ]
 testing  <- dataR[ -Train, ]

model_rf  <- train(  Class~.,  tuneLength=3,  data = training, method = 
"rf",  importance=TRUE,  trControl = trainControl (method = "cv", number = 
5))

结果:

Random Forest 

3006 samples
82 predictor
2 classes: 'NO', 'YES' 

No pre-processing
Resampling: Cross-Validated (5 fold) 
Summary of sample sizes: 2405, 2406, 2405, 2404, 2404 
Addtional sampling using SMOTE

Resampling results across tuning parameters:

 mtry  Accuracy   Kappa    
  2    0.7870921  0.2750655
  44    0.7787721  0.2419762
 87    0.7767760  0.2524898

Accuracy was used to select the optimal model using  the largest value.
The final value used for the model was mtry = 2.

到目前为止还好,但当我运行此代码时:

# Apply threshold of 0.50: p_class
class_log <- ifelse(model_rf[,1] > 0.50, "YES", "NO")

# Create confusion matrix
p <-confusionMatrix(class_log, testing[["Class"]])

##gives the accuracy
p$overall[1]

 Error in model_rf[, 1] : incorrect number of dimensions

如果你们能帮我得到混乱矩阵的结果,我将不胜感激。

4 回复 | 直到 7 年前

missuse 5 年前

为此,您需要指定 savePredictions 在里面 trainControl . 如果设置为 "final" 保存了对最佳模型的预测。通过指定 classProbs = T 还将保存每个类的概率。

data(iris)
iris_2 <- iris[iris$Species != "setosa",] #make a two class problem
iris_2$Species <- factor(iris_2$Species) #drop levels

library(caret)
model_rf  <- train(Species~., tuneLength = 3, data = iris_2, method = 
                       "rf", importance = TRUE,
                   trControl = trainControl(method = "cv",
                                            number = 5,
                                            savePredictions = "final",
                                            classProbs = T))

预测包括:

model_rf$pred

按照CV-fols排序,按原始数据框排序:

model_rf$pred[order(model_rf$pred$rowIndex),2]

要获得混淆矩阵:

confusionMatrix(model_rf$pred[order(model_rf$pred$rowIndex),2], iris_2$Species)
#output
Confusion Matrix and Statistics

            Reference
Prediction   versicolor virginica
  versicolor         46         6
  virginica           4        44

               Accuracy : 0.9            
                 95% CI : (0.8238, 0.951)
    No Information Rate : 0.5            
    P-Value [Acc > NIR] : <2e-16         

                  Kappa : 0.8            
 Mcnemar's Test P-Value : 0.7518         

            Sensitivity : 0.9200         
            Specificity : 0.8800         
         Pos Pred Value : 0.8846         
         Neg Pred Value : 0.9167         
             Prevalence : 0.5000         
         Detection Rate : 0.4600         
   Detection Prevalence : 0.5200         
      Balanced Accuracy : 0.9000         

       'Positive' Class : versicolor

sapply(1:40/40, function(x){
  versicolor <- model_rf$pred[order(model_rf$pred$rowIndex),4]
  class <- ifelse(versicolor >=x, "versicolor", "virginica")
  mat <- confusionMatrix(class, iris_2$Species)
  kappa <- mat$overall[2]
  res <- data.frame(prob = x, kappa = kappa)
  return(res)
})

此处未获得最高kappa threshold == 0.5 但在0.1。应小心使用,因为这可能会导致过度装配。

Hardik Gupta 7 年前

您可以尝试创建混淆矩阵并检查准确性

m <- table(class_log, testing[["Class"]])
m   #confusion table

#Accuracy
(sum(diag(m)))/nrow(testing)

Samuel 7 年前

class_log <- ifelse(model_rf[,1] > 0.50, "YES", "NO") 是执行以下测试的if-else语句:

在 model_rf ,如果数字大于0.50,则返回“YES”,否则返回“NO”,并将结果保存在object中 class_log .

Victor Kostyuk 7 年前

您需要将模型应用于测试集。

prediction.rf <- predict(model_rf, testing, type = "prob")

class_log <- ifelse(prediction.rf > 0.50, "YES", "NO")