如何按指定条件对zip对象列表进行排序?

我对这个问题的看法是:

from itertools import chain

names = ['78', '1', '3']
prices = ['15', '20', '10']

names2 = ['82', '11', '33']
prices2 = ['1', '2', '100']

all_subpages = []

subpage = zip(names, prices)
all_subpages.append(subpage)

subpage2 = zip(names2, prices2)
all_subpages.append(subpage2)

print('Home number\tprice')
for (name, price) in sorted(chain.from_iterable(all_subpages), key=lambda v: int(v[1])):
    print(f'{name}\t\t{price} GBP')

输出:

 Home number    price
82      1 GBP
11      2 GBP
3       10 GBP
78      15 GBP
1       20 GBP
33      100 GBP

鉴于:

l1=["Apartment 1", "Apartment 3","Apartment 2"]
l2=['15 GBP','10 GBP','20 GBP'] 

你可以在字典上对第二个元素进行排序,如下所示:

>>> sorted(zip(l1,l2), key=lambda t: t[1])
[('Apartment 3', '10 GBP'), ('Apartment 1', '15 GBP'), ('Apartment 2', '20 GBP')]

如果你想在数字上做同样的事情,你可以做如下的事情:

>>> sorted(zip(l1,l2), key=lambda t: float(t[1].split()[0]))