Rx:可观察到的力至少需要N秒才能完成

您可以使用 forkJoin 等待两个观察点完成:

Observable.forkJoin(myObservable, Observable.timer(N), data => data)
  .subscribe(...);

对于没有不推荐的结果选择器函数的RxJS 6:

forkJoin(myObservable, Observable.timer(N)).pipe(
  map(([data]) => data),
)
.subscribe(...);

编辑:如评论中所述, Observable.timer(N) take(1) .

forkjoin

我喜欢在我的开发系统上增加更大的延迟,因为我认为生产会更慢。 Observable.timer 似乎不再可用,但您可以使用 timer 直接地

forkJoin(

  // any observable such as your service that handles server coms
  myObservable,

  // or http will work like this
  // this.http.get( this.url ),

  // tune values for your app so very quick loads don't look strange
  timer( environment.production ? 133 : 667 ),

).subscribe( ( response: any ) => {

  // since we aren't remapping the response you could have multiple
  // and access them in order as an array
  this.dataset = response[0] || [];

  // the delay is only really useful if some visual state is changing once loaded
  this.loading = false;

});