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python如何将字典字符串转换为相应的字典?

string json python

Yingqiang Gao · 技术社区 · 4 年前

'{"paper_id": "94550656", "_pdf_hash": "42b3e1bd9c4740192f22d8725d470218e86301c8", "abstract": [], "body_text": [], "bib_entries": {"BIBREF0": {"title": "Solving ratio-dependent predator-prey system with constant effort harvesting using homotopy perturbation method", "authors": [{"first": "R", "middle": ["G"], "last": "Abdoul", "suffix": ""}, {"first": "A", "middle": [], "last": "Barari", "suffix": ""}, {"first": "D", "middle": ["D"], "last": "Ganji", "suffix": ""}], "year": 2008, "venue": "J. Math. Prob. Eng", "link": "16827035"}, "BIBREF1": {"title": "Numerical analysis of strongly nonlinear oscillation systems using He\'s max-min method", "authors": [{"first": "H", "middle": [], "last": "Babazadeh",.....

我怎样才能把它转换成普通字典以便进一步处理? ########################################

代码如下:

json_list = []
with open(s2orc_path, 'r') as s2orcReader:
for line in s2orcReader.readlines():
    json_list.append(line)
s2orc_samples = json.dumps(json_list)
s2orc_data = json.loads(s2orc_samples)

在这之后当我试着 ast.literal_eval(s2orc_data[0]) ValueError: malformed node or string

0 回复 | 直到 4 年前

Zaraki Kenpachi 4 年前

import json

data = """{"paper_id": "94550656", "_pdf_hash": "42b3e1bd9c4740192f22d8725d470218e86301c8", "abstract": [], "body_text": [], "bib_entries": {"BIBREF0": {"title": "Solving ratio-dependent predator-prey system with constant effort harvesting using homotopy perturbation method", "authors": [{"first": "R", "middle": ["G"], "last": "Abdoul", "suffix": ""}, {"first": "A", "middle": [], "last": "Barari", "suffix": ""}, {"first": "D", "middle": ["D"], "last": "Ganji", "suffix": ""}], "year": 2008, "venue": "J. Math. Prob. Eng", "link": "16827035"}}}"""""
dictionary_data = json.loads(data)

Luke_ 4 年前

你可以用json.loads为此:

import json

str = "'[{"age":"luke", "id":0}, {"age":"bob", "id":1}]'"
dict = json.loads(str)
print(str) # [{u'age': u'luke', u'id': 0}, {u'age': u'bob', u'id': 1}]

-2

finn b 4 年前

dictionary = dict(your_dictionary_string)
如果不起作用,使用 json json.loads(your_dictionary_string)

-3

itprorh66 4 年前

您可以尝试将输入字符串拆分为逗号,如下所示:

ps = input_string.spit(",")

在colon mlike上拆分ps的每个元素:

for seg in ps:
  k = seg.split(":")
  out_dict[k[0]] = k[1]

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