在unix shell中添加一列数字

... | paste -sd+ - | bc

是我找到的最短的(从 UNIX Command Line 博客)。

编辑: 增加了 - 关于便携性的争论,谢谢@dogbert和@owen。

这里去

cat files.txt | xargs ls -l | cut -c 23-30 | 
  awk '{total = total + $1}END{print total}'

如果文件名中有空格,则cat将不起作用。这里是一个PerlOne的内衬。

perl -nle 'chomp; $x+=(stat($_))[7]; END{print $x}' files.txt

而不是使用 切 从的输出中获取文件大小 LS-L ,您可以直接使用:

$ cat files.txt | xargs ls -l | awk '{total += $5} END {print "Total:", total, "bytes"}'

awk将“$5”解释为第五列。这是来自 LS-L 这就提供了文件大小。

cat files.txt | xargs ls -l | cut -c 23-30 | python -c'import sys; print sum(int(x) for x in sys.stdin)'

TMTWWTDI :perl有一个文件大小运算符(-s)

perl -lne '$t+=-s;END{print $t}' files.txt

我会用“du”来代替。

$ cat files.txt | xargs du -c | tail -1
4480    total

如果您只想要号码:

cat files.txt | xargs du -c | tail -1 | awk '{print $1}'

如果只想在不使用awk或其他解释器的情况下使用shell脚本,则可以使用以下脚本:

#!/bin/bash

total=0

for number in `cat files.txt | xargs ls -l | cut -c 23-30`; do
   let total=$total+$number
done

echo $total

在KSH:

echo " 0 $(ls -l $(<files.txt) | awk '{print $5}' | tr '\n' '+') 0" | bc

整个L-L和切割都很复杂 斯达 . 它也容易受到 LS-L (直到我更改了 切 )

此外,固定 useless use of cat .

<files.txt  xargs stat -c %s | paste -sd+ - | bc

如果没有安装BC,请尝试

echo $(( $(... | paste -sd+ -) ))

而不是

... | paste -sd+ - | bc

$( ) <--返回执行命令的值

$(( 1+2 )) <--返回评估结果

echo <--将其反射到屏幕上

管道:

 cat files.txt | xargs ls -l | cut -c 23-30 | gawk 'BEGIN { sum = 0 } // { sum = sum + $0 } END { print sum }'

这是我的

cat files.txt | xargs ls -l | cut -c 23-30 | sed -e :a -e '$!N;s/\n/+/;ta' | bc

#
#       @(#) addup.sh 1.0 90/07/19
#
#       Copyright (C) <heh> SjB, 1990
#       Adds up a column (default=last) of numbers in a file.
#       95/05/16 updated to allow (999) negative style numbers.


case $1 in

-[0-9])

        COLUMN=`echo $1 | tr -d -`

        shift

;;

*)

        COLUMN="NF"

;;

esac

echo "Adding up column .. $COLUMN .. of file(s) .. $*"

nawk  ' OFMT="%.2f"                                       # 1 "%12.2f"

        { x = '$COLUMN'                                   # 2

          neg = index($x, "$")                            # 3

          if (neg > 0) X = gsub("\\$", "", $x)

          neg = index($x, ",")                            # 4

          if (neg > 1) X = gsub(",", "", $x)

          neg = index($x, "(")                            # 8 neg (123 & change

          if (neg > 0) X = gsub("\\(", "", $x)

          if (neg > 0) $x = (-1 * $x)                     # it to "-123.00"

          neg = index($x, "-")                            # 5

          if (neg > 1) $x = (-1 * $x)                     # 6

          t += $x                                         # 7

          print "x is <<<", $x+0, ">>> running balance:", t

        } ' $*


# 1.  set numeric format to eliminate rounding errors
# 1.1 had to reset numeric format from 12.2f to .2f 95/05/16
#     when a computed number is assigned to a variable ( $x = (-1 * $x) )
#     it causes $x to use the OFMT so -1.23 = "________-1.23" vs "-1.23"
#     and that causes my #5 (negative check) to not work correctly because
#     the index returns a number >1 and to the neg neg than becomes a positive
#     this only occurs if the number happened to b a "(" neg number
# 2.  find the field we want to add up (comes from the shell or defaults
#     to the last field "NF") in the file
# 3.  check for a dollar sign ($) in the number - if there get rid of it
#     so we may add it correctly - $12 $1$2 $1$2$ $$1$$2$$ all = 12
# 4.  check for a comma (,) in the number - if there get rid of it so we
#     may add it correctly - 1,2 12, 1,,2 1,,2,, all = 12   (,12=0)
# 5.  check for negative numbers
# 6.  if x is a negative number in the form 999- "make" it a recognized
#     number like -999 - if x is a negative number like -999 already
#     the test fails (y is not >1) and this "true" negative is not made
#     positive
# 7.  accumulate the total
# 8.  if x is a negative number in the form (999) "make it a recognized
#     number like -999
# * Note that a (-9) (neg neg number) returns a postive
# * Mite not work rite with all forms of all numbers using $-,+. etc. *

我喜欢用……

echo "
1
2
3 " | sed -e 's,$, + p,g' | dc 

它们将显示每行的总和…

适用于这种情况:

ls -ld $(< file.txt) | awk '{print $5}' | sed -e 's,$, + p,g' | dc 

合计是最后一个值…

在我看来,最简单的解决方案是“expr”unix命令:

s=0; 
for i in `cat files.txt | xargs ls -l | cut -c 23-30`
do
   s=`expr $s + $i`
done
echo $s

纯巴什

total=0; for i in $(cat files.txt | xargs ls -l | cut -c 23-30); do 
total=$(( $total + $i )); done; echo $total

sizes=( $(cat files.txt | xargs ls -l | cut -c 23-30) )
total=$(( $(IFS="+"; echo "${sizes[*]}") ))

或者你可以一边读尺寸一边求和。

declare -i total=0
while read x; total+=x; done < <( cat files.txt | xargs ls -l | cut -c 23-30 )

如果你不在乎咬口大小和咬块大小,那么

declare -i total=0
while read s junk; total+=s; done < <( cat files.txt | xargs ls -s )

cat files.txt | awk '{ total += $1} END {print total}'

你可以用awk做同样的事情,它甚至跳过非整数。

$ cat files.txt
1
2.3
3.4
ew
1

$ cat files.txt | awk '{ total += $1} END {print total}'
7.7

或者可以使用ls命令计算人类可读的输出

$ ls -l | awk '{ sum += $5} END  {hum[1024^3]="Gb"; hum[1024^2]="Mb"; hum[1024]="Kb"; for (x=1024^3; x>=1024; x/=1024) { if (sum>=x) { printf "%.2f %s\n",sum/x,hum[x]; break; } } if (sum<1024) print "1kb"; }'
15.69 Mb

$ ls -l *.txt | awk '{ sum += $5} END  {hum[1024^3]="Gb"; hum[1024^2]="Mb"; hum[1024]="Kb"; for (x=1024^3; x>=1024; x/=1024) { if (sum>=x) { printf "%.2f %s\n",sum/x,hum[x]; break; } } if (sum<1024) print "1kb"; }'
2.10 Mb