使用lambda表达式的枚举重写方法

我有两种解决方案,一种是使用一个构成比较器库的枚举:

public enum SongComparator {

    BY_TITLE(Comparator.comparing(Song::getTitle)),
    BY_ARTIST(Comparator.comparing(Song::getArtist)),
    BY_DURATION(Comparator.comparing(Song::getDuration));

    private Comparator<Song> comp;

    private SongComparator(Comparator<Song> comp) {
        this.comp = comp;
    }

    public Comparator<Song> get() {
        return comp;
    }
}

和

public enum SongComparator2 implements Comparator<Song> {

    BY_TITLE {
        public int compare(Song s1, Song s2) {
            return s1.getTitle().compareTo(s2.getTitle());
        };
    },
    BY_ARTIST {
        public int compare(Song s1, Song s2) {
            return s1.getArtist().compareTo(s2.getArtist());
        };
    },
    BY_DURATION {
        public int compare(Song s1, Song s2) {
            return Integer.compare(s1.getDuration(), s2.getDuration());
        };
    };

}

如果我想在需要Comparator的地方替换一个枚举值,在第一个解决方案中,我必须说SongComparator.BY_TITLE。获取();而在第二个解决方案中,我只能说SongComparator2.BY_TITLE。

从这个意义上讲,第二种方法更好,但是,我不喜欢为每个枚举值编写公共int compare…etc,而是希望使用Comparator。与第一种方法一样进行比较。有办法做到这一点吗?

我几乎想说这样的话:BY_TITLE{return Comparator.comparing(Song::getTitle);};