如何在客户端知道是否发生了回发?

不用费力地检查回邮。这几乎总是一种痛苦的做事方式。你关心表的内容,监督它。

请参阅:

1. Run Greasemonkey script on the same page, multiple times?
2. Fire Greasemonkey script on AJAX request
3. How can I detect AJAX node insertion without using DOM mutation events?

以及其他几个。

正如Brock Adams在回答中所说,我决定监视这个表,并编写了以下代码:

function repairInputEvents() {
    for (var i = 0; i < document.getElementsByTagName("input").length; i++) {
        //Add event to buttons that cause postback.
        document.getElementsByTagName("input")[i].addEventListener("click", function() {

            //Run the following just before postback.
            document.getElementsByClassName("table")[0].setAttribute("title", "old");
            var checkAjaxInterval = setInterval(function() { checkAjax(); }, 1000);

            function checkAjax() {
                if (document.getElementsByClassName("table")[0].getAttribute("title") != "old") {
                    clearInterval(checkAjaxInterval);
                    repairInputEvents();
                    repairSelectEvents();
                }
            }

        });

    }
}

//First run
repairInputEvents();
repairSelectEvents();