比较两个列表,并创建具有交叉和差异的其他两个列表

#to create a list with ids that are in A and found in B (unique)
resultlist=list(set(A)&set(B))
print(list(set(A)&set(B)))


#to create a list of ids that are in A and have no corresponding in B (unique)
print(list(set(A)-set(B)))


#the numbers in B, that don't have a corespondent in A
print(list(set(B)-set(A)))

将列表转换为 set

>>> set_A = set(A)
>>> set_B = set(B)
>>> list(set_A & set_B)
[1, 3, 5, 7, 9, 14]         # set intersection

>>> list(set_A - set_B)     # set difference
[12]

>>> list(set_B - set_A)
[2]

对于python,您可以简单地使用set类型:

list(set(A) & set(B))

A 和 B .

list(set(A) - set(B))

将返回一个包含中所有元素的列表 A 而不是在 .

反之亦然:

list(set(B) - set(A))

将返回一个包含中所有元素的列表 B 而不是在 .

您可以使用'a in L'功能,如果元素在列表中,该功能将返回True。例如

A = [1,3,5,7, 9, 12, 14]
B = [1,2,3,3,7,9,7,3,14,14,1,3,2,5,5]

common = []
uncommon = []

for a in A:
    if a in B:
      common.append(a)
    else:
      uncommon.append(a)
print(common)
print(uncommon)

这会给你一个很好的提示,告诉你如何处理另一个问题。

set operations

A = [1, 3, 5, 7, 9, 12, 14]
B = [1, 2, 3, 3, 7, 9, 7, 3, 14, 14, 1, 3, 2, 5, 5]

sa = set(A)
sb = set(B)

# intersection
l1 = list(sa & sb)
# [1, 2, 3, 5, 7, 9, 12, 14]

# differences
l2 = list(sa - sb)
# [12]
l3 = list(sb - sa)
# [2]