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把数组放到foreach之后就不能算了?

foreach arrays php

Bijan Zand · 技术社区 · 5 年前

我应该找到今天的时间戳,如果计数超过3则返回false如果不返回true

查询:

while( $record = $result->fetchAssoc() ) { 
    $items[] = $record;
}

输出:

Array
(
    [0] => Array
        (
            [timestamp] => 1570877769
        )

    [1] => Array
        (
            [timestamp] => 1570877783
        )

    [2] => Array
        (
            [timestamp] => 1510877794
        )

)

foreach公司:

    foreach ($items as $Newarrays) {

    }

使用foreach循环外观之后:

Array
(
    [timestamp] => 1570877769
)
Array
(
    [timestamp] => 1570877783
)
Array
(
    [timestamp] => 1570877794
)

这一步我要数数 timestamp 今天要找到3个时间戳,但是 count 返回 1 不工作!

更新完整代码:

$query->condition('node_revision.nid', $node->nid);

$result = $query->execute();

    while( $record = $result->fetchAssoc() ) { 
        $items[] = $record;
    }


foreach ($items as $Newarrays) {


    $timestamp=$Newarrays["timestamp"];
    $accessdate=format_date($timestamp, 'custom', 'd-m-Y' );
    $currentdate=date("d-m-Y");



    if ($accessdate === $currentdate) {
         if (count( $accessdate > 3 )) {
            print_r ($accessdate);
        }

    }

}

怎么做到的? 谢谢你的帮助…

1 回复 | 直到 5 年前

Dilip Hirapara 5 年前

像这样试试。在这个输出中,我得到一个 count 作为 2

   $items = array(array('timestamp'=>1570877769),array('timestamp'=>1570877783),array('timestamp'=>1510877794));


    $currentdate=date("d-m-Y");

    $count = 0;
    foreach ($items as $newarrays) {
        if($currentdate == date("d-m-Y",$newarrays['timestamp'])){
            $count++;
        }
    }
    echo $count;
    exit;

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