内联调用失败,代码大小将增长[-Winline],但不使用内联

这对C++来说是非常新鲜的。

以下是用户定义的fmiNode类:(fmi.h)

class fmiNode
{
public:
    fmiNode(std::string NodeName,int Address)
    {
        this->name = NodeName;
        this->address = Address;
    }

    std::string GetName()
    {
    return this->name;
    }

    int GetAddress()
    {
    return this->address;
    }

private:
    std::string name;
    int address;
};

这是我的主要方法(fmi.c)

int main (int argc, char *argv[])
{
  fmiNode node1("NodeA",4);
  fmiNode node2("NodeB",6);
  fmiNode node3("NodeC",8);
  fmiNode node4("NodeD",10);

  while(1)
  {
      MainLoop();
  }
}

如果我只实例化一个fmiNode对象,一切都很好。但以下3项会引发警告:

 warning: inlining failed in call to ‘fmiNode::fmiNode(std::string, int)’: call is unlikely and code size would grow [-Winline]

我在这里做错了什么。

编辑:

所以我应该这样定义我的类:?

class fmiNode
{
public:
    fmiNode(std::string NodeName,int Address);

    std::string GetName()
    {
    return this->name;
    }

    int GetAddress()
    {
    return this->address;
    }

private:
    std::string name;
    int address;
};

fmiNode::fmiNode(std::string NodeName,int Address)
{
    this->name = NodeName;
    this->address = Address;
}

干杯 里斯