如何将结构数组的每个元素传递到函数中?

#include<stdio.h>
#include<string.h>

struct students{
    char name[50];
    int marks;
}st[10];


int size;

int addStudent(struct students st,char sname[], int marks){
    static int count = 0;
    strncpy(st.name,sname,strlen(sname));
    st.marks = marks;
    count++;
    return count;
}

void showStudents(int size){
    int i;
    printf("Total number of students : %d\n",size);
    for(i=0;i<size;i++){
        printf("Student Name : %s\nMarks : %d\n",st[i].name,st[i].marks);
    }   
}

int main(){
    int n, marks, i;
    char name[50];
    printf("Enter the total number of students : ");
    scanf("%d",&n);
    getchar();
    for(i=0;i<n;i++){
        printf("Enter the name of the Student : ");
        fgets(name,50,stdin);
        printf("Enter the marks of the student : ");
        scanf("%d",&marks);
        getchar();
        size = addStudent(st[i], name, marks);
    }

    showStudents(size);

    return 0;
}

我得到以下输出

Enter the total number of students : 2
Enter the name of the Student : shibli
Enter the marks of the student : 23
Enter the name of the Student : max
Enter the marks of the student : 45
Total number of students : 2
Student Name :
Marks : 0
Student Name :
Marks : 0