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从PSCustomObject类型的数组中获取值

powershell

Dmitrij Kultasev · 技术社区 · 6 年前

PSCustomObject 找不到正确的路。

PS: $val
  entry1 : @{order=10; isConditionalDeploy=1; isDropExtendedProperties=0}
  entry2 : @{order=20; isConditionalDeploy=1; isDropExtendedProperties=0}
  entry3 : @{order=30; isConditionalDeploy=1; isDropExtendedProperties=0}

PS: $val.GetType()
  IsPublic IsSerial Name     BaseType
  -------- -------- ----     --------
  True     True     Object[] System.Array

PS: $val[0]
  entry1 : @{order=10; isConditionalDeploy=1; isDropExtendedProperties=0}
  entry2 : @{order=20; isConditionalDeploy=1; isDropExtendedProperties=0}
  entry3 : @{order=30; isConditionalDeploy=1; isDropExtendedProperties=0}

PS: $val[0].GetType()
  IsPublic IsSerial Name           BaseType
  -------- -------- ----           --------
  True     False    PSCustomObject System.Object

我试了这么多方法,结果总是一样的。我试着从 $val.PSObject 但运气不好

$val | gm
Name              MemberType   Definition
----              ----------   ----------
Equals            Method       bool Equals(System.Object obj)
GetHashCode       Method       int GetHashCode()
GetType           Method       type GetType()
ToString          Method       string ToString()
entry1            NoteProperty System.Management.Automation.PSCustomObject entry1=@{order=10; isConditionalDeploy=1;
entry2            NoteProperty System.Management.Automation.PSCustomObject entry2=@{order=20; isConditionalDeploy=1; 
entry3            NoteProperty System.Management.Automation.PSCustomObject entry3=@{order=30; isConditionalDeploy=1;

0 回复 | 直到 6 年前

Ben Richards 6 年前

如果您只是尝试访问这些值,则应该可以:

$json = '{
"entry1":
    {
        "order":"10",
        "isConditionalDeploy":"1",
        "isDropExtendedProperties":"0"
    },
"entry2":
    {
        "order":"20",
        "isConditionalDeploy":"1",
        "isDropExtendedProperties":"0"
    }
}'

$val = $json | ConvertFrom-Json

$val | ForEach-Object {
    $_.PSObject.Properties.Value
}

输出

order isConditionalDeploy isDropExtendedProperties
----- ------------------- ------------------------
10    1                   0
20    1                   0

AdminOfThings 6 年前

$val.psobject.properties.name

要列出所有属性值,请运行以下命令:

$val.psobject.properties.value

$val.psobject.properties.name 和 $值.psobject.properties.名称 $val.psobject.properties.name[0] $val.psobject.properties.value[0] .

如果您已经知道属性名并且只需要值,那么可以按照Theo的建议访问值。

{
"entry1":
    {
        "order":"10",
        "isConditionalDeploy":"1",
        "isDropExtendedProperties":"0"
    },
"entry2":
    {
        "order":"20",
        "isConditionalDeploy":"1",
        "isDropExtendedProperties":"0"
    }
}

$val

$val = Get-Content json.json | ConvertFrom-Json
$val | fl

entry1 : @{order=10; isConditionalDeploy=1; isDropExtendedProperties=0}
entry2 : @{order=20; isConditionalDeploy=1; isDropExtendedProperties=0}

$val | gm

   TypeName: System.Management.Automation.PSCustomObject

   TypeName: System.Management.Automation.PSCustomObject

    Name        MemberType   Definition
    ----        ----------   ----------
    Equals      Method       bool Equals(System.Object obj)
    GetHashCode Method       int GetHashCode()
    GetType     Method       type GetType()
    ToString    Method       string ToString()
    entry1      NoteProperty Object[] entry1=System.Object[]
    entry2      NoteProperty Object[] entry2=System.Object[]

完成以上所有操作后,我的属性名和值检索就如我所建议的那样工作。你能提供你的JSON文件内容吗?

Walter Mitty 6 年前