在python中测试套接字连接

似乎你没有抓住你想抓住的例外:)

如果 s 是一个 socket.socket() 对象,然后调用正确的方法 .connect 将是:

import socket
s = socket.socket()
address = '127.0.0.1'
port = 80  # port number is a number, not string
try:
    s.connect((address, port)) 
    # originally, it was 
    # except Exception, e: 
    # but this syntax is not supported anymore. 
except Exception as e: 
    print("something's wrong with %s:%d. Exception is %s" % (address, port, e))
finally:
    s.close()

总是试着看看在一个Try-Except循环中你会捕获什么样的异常。

您可以检查套接字模块中的异常类型代表什么类型的错误(超时、无法解析地址等),并将它们分开 except 对每一个问题的陈述-这样你就可以对不同类型的问题做出不同的反应。

你可以使用这个功能 connect_ex . 它不会引发异常。而不是返回C样式的整数值(称为 errno C):

s =  socket.socket(socket.AF_INET, socket.SOCK_STREAM)
result = s.connect_ex((host, port))
s.close()
if result:
    print "problem with socket!"
else:
    print "everything it's ok!"

你真的应该发布:

1. 示例的完整源代码
2. 这个 实际的 结果,不是总结

这是我的代码,它起作用:

import socket, sys

def alert(msg):
    print >>sys.stderr, msg
    sys.exit(1)

(family, socktype, proto, garbage, address) = \
         socket.getaddrinfo("::1", "http")[0] # Use only the first tuple
s = socket.socket(family, socktype, proto)

try:
    s.connect(address) 
except Exception, e:
    alert("Something's wrong with %s. Exception type is %s" % (address, e))

当服务器监听时,我什么也得不到(这是正常的),当它 没有,我得到了预期的信息:

Something's wrong with ('::1', 80, 0, 0). Exception type is (111, 'Connection refused')